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Oksanka [162]
2 years ago
15

A conditional relative frequency table is generated by row from a set of data. The conditional relative frequencies of the two c

ategorical variables are then compared.
If the relative frequencies are 0.48 and 0.52, which conclusion is most likely supported by the data?


A.) There is likely an association between the categorical variables because the relative frequencies are similar in value.

B.) An association cannot be determined between the categorical variables because the relative frequencies are similar in value.

C.) An association cannot be determined between the categorical variables because the relative frequencies are not similar in value.

D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50.
Mathematics
2 answers:
kicyunya [14]2 years ago
7 0

The <em><u>correct answer</u></em> is:

A.) There is likely an association between the categorical variables because the relative frequencies are similar in value.

Explanation:

If the relative frequencies are similar, then there is probably an association between the variables.

If the relative frequencies are not similar, then there is probably not an association between the variables.

Gre4nikov [31]2 years ago
4 0
The right answer for the question that is being asked and shown above is that: "D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50." Given that a relative frequencies of 0.48 and 0.52, there will be an association between the categorical variables.<span>
</span>
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satela [25.4K]

Answer:

t=2.47\ s  

Step-by-step explanation:

The equation that models the height of the ball in feet as a function of time is

h(t) = h_0 + s_0t -16t ^ 2

Where h_0 is the initial height, s_0 is the initial velocity and t is the time in seconds.

We know that the initial height is:

h_0 = 4.5\ ft

The initial speed is:

s_0 = 110sin(20\°)\\\\s_0 = 37.62\ ft/s

So the equation is:

h (t) = 4.5 + 37.62t -16t ^ 2

The ball hits the ground when when h(t) = 0

So

4.5 + 37.62t -16t ^ 2 = 0

We use the quadratic formula to solve the equation for t

For a quadratic equation of the form

at^2 +bt + c

The quadratic formula is:

t=\frac{-b\±\sqrt{b^2 -4ac}}{2a}

In this case

a= -16\\\\b=37.62\\\\c=4.5

Therefore

t=\frac{-37.62\±\sqrt{(37.62)^2 -4(-16)(4.5)}}{2(-16)}

t_1=-0.114\ s\\\\t_2=2.47\ s  

We take the positive solution.

Finally the ball takes 2.47 seconds to touch the ground

4 0
2 years ago
Let X, the number of flaws on the surface of a randomly selected boiler of a certain type, have a Poisson distribution with para
kvasek [131]

Answer:

(a) 0.932

(b) 0.0653

(c) 0.032

(d) 0.316

(e) 0.251

Step-by-step explanation:

From the table with mean parameter μ = 5, we can compute the following cumulative and density probability

(a) P(X \leq 8) = 0.932 (cumulative)

(b) P(X = 8) = 0.0653 (density)

(c) P(9 \leq X) = 1 - P(X \leq 9) = 1 - 0.968 = 0.032 (cumulative)

(d) P(5 \leq X \leq 8) = P(X \leq 8) - P(X \leq 5) = 0.932 - 0.616 = 0.316 (cumulative)

(e) P(5 < X < 8) = P(X \leq 8) - P(X \leq 5) - P(X = 8) = 0.932 - 0.616 - 0.0653 = 0.251

5 0
2 years ago
If Line segment C B. bisects ∠ACD, what additional information could be used to prove ΔABC ≅ ΔDBC using SAS? Select three option
meriva

Answer:

Option (1)

Step-by-step explanation:

In the figure attached,

BC is the angle bisector of angle ACD.

To prove ΔABC and ΔDBC congruent by SAS property we require two sides and the angle between these sides to be congruent.

Since BC ≅ BC [Reflexive property]

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And sides AB ≅ BD

Both the triangles will be congruent.

Therefore, additional information required to prove ΔABC ≅ ΔDBC have been given in option (1).

Therefore, Option (1) will be the answer.

3 0
2 years ago
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1 year ago
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x + y = 28 \\ x = 28 - y

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Answer : He has 16 quarters.

Hope this helps. - M
5 0
2 years ago
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