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Oksanka [162]
2 years ago
15

A conditional relative frequency table is generated by row from a set of data. The conditional relative frequencies of the two c

ategorical variables are then compared.
If the relative frequencies are 0.48 and 0.52, which conclusion is most likely supported by the data?


A.) There is likely an association between the categorical variables because the relative frequencies are similar in value.

B.) An association cannot be determined between the categorical variables because the relative frequencies are similar in value.

C.) An association cannot be determined between the categorical variables because the relative frequencies are not similar in value.

D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50.
Mathematics
2 answers:
kicyunya [14]2 years ago
7 0

The <em><u>correct answer</u></em> is:

A.) There is likely an association between the categorical variables because the relative frequencies are similar in value.

Explanation:

If the relative frequencies are similar, then there is probably an association between the variables.

If the relative frequencies are not similar, then there is probably not an association between the variables.

Gre4nikov [31]2 years ago
4 0
The right answer for the question that is being asked and shown above is that: "D.) There is likely an association between the categorical variables because the relative frequencies are both close to 0.50." Given that a relative frequencies of 0.48 and 0.52, there will be an association between the categorical variables.<span>
</span>
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1. Write an exponential function to represent the spread of Ben's social media post. 2. Write an exponential function to represe
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Answer:

1. y = 2(3)ˣ; 2. y = 10(4)^x; 4. Amber = 192 and 3 145 728;

Ben has 54 and 11 098; Carter = 80 and 10 249 shares;

5. Shifted up 45 shares; 6. Amber's;

7. Fewer friends. more shares.

Step-by-step explanation:

The general equation for an exponential function is

y = a(b)ˣ

1. Ben's function

The initial value a = 2.

6 = 2(b)¹ = 2b

Ben's function is  

y = 2(3)^x

2. Carter's function

Carter shared his post with 10 friends on Day 0, so  a= 10.  

Each friend shared with 2 people each day, so b = 2.

Therefore, Carter's function is

y=10(2)ˣ

3. Graphs

\begin{array}{cccc}& \textbf{Amber} &\textbf{Ben}  & \textbf{Carter}\\\mathbf{x} & \mathbf{3(4)^{x}} &\mathbf{2(3)^{x}} & \mathbf{10(2)^{x}}\\0 & 3 & 2 & 10\\1 & 12 & 6 & 20\\2 & 48 & 18 & 40\\3 & 192 & 54 & 80\\\end{array}

The figure below shows the graphs for each function.

4. Predictions

(a) Amber

(i) Day 3

y = 3(4)³  = 3 × 64 = 192

(ii) Day 10

y = 3(4)¹⁰  = 3 × 1 048 576 = 3 145 728

(b) Ben

(i) Day 3

y = 2(3)³  = 2 × 27 = 54

(ii) Day 10

y = 2(3)¹⁰  = 2 × 29 049 = 118 098

(c) Carter

(i) Day 3

y = 10(2)³  = 10 × 8 = 80

(ii) Day 10

y =10(2)¹⁰  = 10 × 1024 = 10 240

5. Sharing with assisted living facility

y = 3(4)ˣ + 45

The new graph will be shifted up by 45 units.

6. Fastest post

Amber's post travels the fastest.

After only two days, she already has more posts than anyone else.

By Day 10, she has more than 25 times the shares of her closest competitor.

7. Preference

It's not the number of friends you have, but the number of shares they make, that is the important factor.

Carter started with 10 friends, but they made only two shares.

Amber started with only three friends, but they made four shares. By Day 3, she had 192 shares compared to 82 for Carter and only 54 for Ben

If I had to choose, I would prefer a post with fewer friends initially but more shares, like Amber.

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