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stich3 [128]
2 years ago
13

If f(x) = 2-x1/2 and if g(x) = x2-9, what is the domain of g(x) / f(x)

Mathematics
1 answer:
Yuliya22 [10]2 years ago
4 0
G(x)/f(x)= (x²-9)/(2-√x)

the domain is (0, ∞).

because 0 makes function undefined and  the function is positive.
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A 20-person fraternity is making their weekend plans around 5 different parties in IV. Each brother will attend exactly one of t
skad [1K]

Answer:

3876

Step-by-step explanation:

Given the following :

Fraternity members = 20

They are to attend 5 different parties in groups of 4

Meaning a group = 4 persons

Atleast one brother will attend exactly one of the parties. (the brothers are indistinguishable).

Then, exactly one brother at a party (20 - 1) = 19, since they are indistinguishable.

Group members are in 4's

19C4

From: nCr = n! /(n-r)! r!

19C4 = 19! / (19 - 4)! 4!

= 19! / 15! 4!

= (19 * 18 * 17 * 16) / (4 * 3 * 2)

= 93024 / 24

= 3876

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2 years ago
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Blababa [14]
I think it is the 2nd one

5 0
2 years ago
$36 for 4 baseball hats; $56 for 7 baseball hats are they equivalent
Arlecino [84]
36/4 = 9 per hat
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5 0
2 years ago
If f(1) = 0 what are all the roots of the function f(x)=x^3+3x^2-x-3 use the remainder theorem.
ArbitrLikvidat [17]

Solution:

As we are given that f(1) = 0 .

It mean that (x-1) is one of the factor of the given equation.

Remainder theorem can be applied as below:

\frac{(x^3+3x^2-x-3)}{(x-1)}=\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}\\ \\\frac{x^3-x^2+4x^2-4x+3x-3}{(x-1)}=\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)} \\\\\frac{x^2(x-1)+4x(x-1)+3(x-1)}{(x-1)}=\frac{(x^2+4x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+4x+3)(x-1)}{(x-1)} =\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  \\\\\frac{(x^2+3x+x+3)(x-1)}{(x-1)}  =\frac{(x-1)(x+3)(x+1)}{(x-1)}

Hence the factors are (x-1),(x+3) and (x+1).

Hence the correct option is B.

5 0
2 years ago
Read 2 more answers
What is the sum of 9.8 and 573.54
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