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1 year ago

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Ayuda es para mañana El estudiante 1 y el estudiante 2 están a 53 metros, uno del otro. El estudiante 1, desde su posición, ve u

na caja fuerte, e inmediatamente mide el ángulo que el mismo forma con el estudiante 2, resultando de 37°. El estudiante 2, al advertirlo , mide enseguida el ángulo que forma la caja fuerte con el estudiante 1, resultando de 43°. ¿cual de los dos se halla más cerca de la caja fuerte?
A. El estudiante 2, ya que está aproximadamente a 32,29 metros.
B. El estudiante 1, ya que está aproximadamente a 32,29 metros.
C. El estudiante 2, ya que está aproximadamente a 37,28 metros.
D. El estudiante 1, ya que está aproximadamente a 37,28 metros.

1 answer:

hram777 [196]1 year ago

6 0

Answer:

La opción correcta es;

Estudiante 2, ya que está aproximadamente a 32,39 metros de distancia

Step-by-step explanation:

Los parámetros dados son;

La distancia entre los dos estudiantes = 53 metros

El ángulo medido entre la línea del Estudiante 1 a la caja fuerte y el Estudiante 1 y el Estudiante 2 = 37 °

El ángulo medido entre la línea del Estudiante 2 a la caja fuerte y el Estudiante 2 y el Estudiante 1 = 43 °

Dado que los dos estudiantes y la caja fuerte forman los vértices de un triángulo, tenemos;

Sea θ el ángulo del triángulo opuesto a la distancia entre los dos estudiantes

Por lo tanto;

θ + 43 ° + 37 ° = 180 ° (teorema de suma de ángulos)

θ = 180 ° - (43 ° + 37 °) = 100 °

Por regla del seno, tenemos;

a / (sin (A) = b / sin (B)

Por lo tanto;

53 / (sin (100 °)) = b / (sin (37 °)) = c / (sin (43 °))

Lo que da;

b = (sin (37 °)) × 53 / (sin (100 °)) = 32,39 metros

c = (sin (43 grados)) × 53 / (sin (100 grados)) = 36,7 metros

Por lo tanto, el Estudiante 2 está más cerca, ya que está aproximadamente a 32,39 metros de distancia.

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Step-by-step explanation:

Given

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2 years ago

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<span>We might assume negative ages to mean before they came into the world, before birth! </span>

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