One thousand seventy two point thirty nine thousandths.
Answer: 0.9332.
Step-by-step explanation:
Claim : College Algebra final exam score of engineering majors equal to 88.
Given that : The test statistic is z equals to 1.50.
To find the p-value (Probability value), we use standard normal distribution table, and search the p-value corresponds to the z-score.
In a Standard Normal Distribution Table below, the p-value corresponds z equals 1.5 is 0.9332.
Hence, the p-value is 0.9332.
Given inequality: 2y−x ≤ −6
Option-1 : (-3,0)
2×0 - (-3) = 0 + 3 = 3 > -6
Not satisfied
Option-2 : (6,1)
2×1 - 6 = 2 - 6 = -4 > -6
Not satisfied
Option-3 : (1, -4)
2×(-4) - 1 = -8 - 1 = -9 < -6
Satisfied.
Thus, (1, -4) is a solution.
Option-4 : (0, -3)
2×(-3) - 0 = -6 - 0 = -6 = -6
Satisfied.
Thus, (0, -3) is a solution.
Option-5 : (2, -2)
2×(-2) - 2 = -4 - 2 = -6 = -6
Satisfied.
Thus, (2, -2) is a solution.
Solutions are: (1, -4), (0, -3) , (2, -2)
As usual, draw a diagram. You can easily see that if you are x away from the wall,
<span>the angle of elevation of the bottom of the screen (A) is </span>
<span>cotA = x/3 </span>
<span>A = arccot(x/3) </span>
<span>angle B to the top is </span>
<span>cotB = x/10 </span>
<span>B = arccot(x/10) </span>
<span>So, since θ = B-A </span>
<span>dθ/dt = dB/dt - dA/dt </span>
<span>= -3/(x^2+9) + 10/(x^2+100) </span>
<span>= 7(x^2-30)/((x^2+9)(x^2+100)) </span>
<span>so, at x=30 </span>
<span>dθ/dt = 203/30300</span>
C. Region D
Step-by-step explanation:
Just plug the equations into desmos the calculator will graph it and show you with colors where the solution is.
