Answer:
1445
Step-by-step explanation:
2601*(9/9-4/9)
Given :
For the school's sports day, a group of students prepared 12 1/2 litres of lemonade. At the end of the day they had 2 5/8 litres left over.
To Find :
How many litres of lemonade were sold.
Solution :
Initial amount of lemonade, I = 12 1/2 = 25/2 litres.
Final amount of lemonade, F = 2 5/8 = 21/8 litres.
Amount of lemonade sold, A = I - F
A = 25/2 - 21/8 litres
A = 9.875 litres
Therefore, 9.875 litres of lemonade were sold.
Hence, this is the required solution.
Answer:
We need a sample size of at least 719
Step-by-step explanation:
We have that to find our
level, that is the subtraction of 1 by the confidence interval divided by 2. So:

Now, we have to find z in the Ztable as such z has a pvalue of
.
So it is z with a pvalue of
, so 
Now, find the margin of error M as such

In which
is the standard deviation of the population and n is the size of the sample.
How large a sample size is required to vary population mean within 0.30 seat of the sample mean with 95% confidence interval?
This is at least n, in which n is found when
. So






Rouding up
We need a sample size of at least 719
Given:
Amount in the bank account = $1850
Monthly payment of can loan = $400.73
To find:
When would automatic payments make the value of the account zero?
Solution:
Craig stops making deposits to that account. So, amount $1850 in the bank account is used to make monthly payment of can loan.
On dividing the amount by monthly payment, we get

It means, the amount is sufficient for 4 payment but for the 5th payment the amount is not sufficient.
Therefore, the 5th automatic payments make the value of the account zero.
To round a number to the nearest hundred, we count two places to the left of the decimal point, or from the last digit if the number is a whole number.
If the second digit from the last digit is upto 5, we add 1 to the preceding digit and we complete the last two numbers with zeros.
Therefore, any number from 11,950 to 12,049, will result to 12,000 when rounded to the nearest hundred.