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ella [17]
1 year ago
15

Square 33 is the first square in Row 5, the first square of the second half of the chessboard. How many pennies are on square 33

?
Mathematics
2 answers:
bulgar [2K]1 year ago
7 0

Answer:

2^{32} is the answer.

Step-by-step explanation:

If we put a penny on the first square of a chess board, 2 on second, six on third and we keep on doing double for the next square then it will form a geometric sequence in the form of T_{n}=2^{n-1}

1, 2, 4, 8, 16.........n terms

Now we have to calculate the pennies on square 33 that will be

So pennies on 33rd square will be

T_{33}=2^{33-1}=2^{32}

Olin [163]1 year ago
4 0
Square 33 is the first square in Row 5, the first square of the second half of the chessboard. How many pennies are on square 33?
Answer : 2^32
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I also need help with this problem.
nadezda [96]

We will use substitution to solve this system of linear equations, as the first equation has x and y with no coefficients, which makes it easier to find one in terms of the other. We can then substitute that value in the other equation and find the values of x and y.

x = y + 5 ---> equation 1

3x + 2y = 5 ---> equation 2

From equation 1, we get the value of x as y + 5. Using the substitution method, we can find the value of y by substituting (y+5) for x in the 2nd equation.

3(y+5) + 2y = 5

3y + 15 + 2y = 5

5y = 5 - 15

5y = -10

y = -2

Subsituting this value of y in (y+5), we can find x.

x = y + 5

x = -2 + 5

x = 3

Therefore, x = 3 and y = -2.

I will also solve this using elimination method.

Let us multiply equation 1 by 2, so that we get 2y in both equations.

2x = 2y + 10

3x + 2y = 5

Let us add both the equations.

2x + 3x + 2y = 5 + 2y + 10

5x = 15 + 2y - 2y

5x = 15

x = 3

Substituting this value of x in equation 1, we get

x = y + 5

3 = y + 5

y = 3 - 5

y = -2

Therefore, x = 3 and y = -2.

7 0
1 year ago
Food allergies affect an estimated 7% of children under age 5 in the US. What is the probability that in a kindergarden class of
bezimeni [28]

Answer:

Probability of atleast one of 12 student has food allergies ≈ 0.58 ( approx)

Step-by-step explanation:

Given: Probability of a children under age 5 has food allergies = 7%

                                                                                                        =\frac{7}{100}

To find : Probability of atleast one of 12 student has food allergies

Probability of a chindren under age 5 does not have food allergies = 1-\frac{7}{100}

                  ⇒ prob = \frac{93}{100}

now we find Probability of atleast one of 12 student has food allergies this means we have to find prob of 1 student, 2 student, 3 student, till 12 student have allergy out of 12 student of class then add all prob.

But instead of finding all these probability we find probability of student having no allergy.i.e., 0 student then subtract it from 1(total probability)

Probability of 0 student having allergy out of 12 student = (\frac{93}{100})^{12}

Therefore, Probability of atleast one of 12 student has food allergies

                  = 1-(\frac{93}{100})^{12}

                  = 0.581403702521

                  ≈ 0.58 ( approx)

                 

8 0
1 year ago
Read 2 more answers
The fish population in a pond with carrying capacity 1200 is modeled by the following logistic equation where N(t) denotes the n
MArishka [77]

9514 1404 393

Answer:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

  142 fish

Step-by-step explanation:

A) The differential equation is modified by adding a -50 fish per year constant term:

  (dN)/(dt) = (0.4)/(1200)N(1200-N) -50

__

B) The steady-state value of the fish population will be when N reaches the value that makes dN/dt = 0.

  (0.4/1200)(N)(1200-N) -50 = 0

  N(N-1200) = -(50)(1200)/0.4) . . . . rewrite so N^2 has a positive coefficient

  N^2 -1200N + 600^2 = -150,000 +600^2 . . . . complete the square

  (N -600)^2 = 210,000 . . . . . simplify

  N = 600 + √210,000 ≈ 1058

This steady-state number of fish is ...

  1200 - 1058 = 142 . . . . below the original carrying capacity

8 0
1 year ago
Casey bought sandwiches and bags of chips. Each sandwich cost three times asmuch as a bag of chips. She bought 5 sandwiches for
Lerok [7]

Answer:

Casey Bought 6 bags of chips

Step-by-step explanation:

If each sandwich costs 3 times the amount of a bag of chips and the sandwich is 6 dollars, the chips are 2 dollars. Casey bought 5 sandwiches and spent $30 dollars on sandwiches. Since the total was $42 dollars you have $12 dollars left to get your total of $42. 2x6 = 12 so therefore Casey bought 6 bags of chips.

5 0
2 years ago
Jose rides his bicycle for 5 minutes to travel 8 blocks. He rides for 10 minutes to travel 16 blocks.
kolbaska11 [484]

Answer:

A=8 B=15 C=40

Step-by-step explanation:

I just took a test

4 0
1 year ago
Read 2 more answers
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