Question

Find the 89th term of the arithmetic sequence -16 -3 10

Answer 1

Answer:

$a_{89}=1128$

Step-by-step explanation:

The given arithmetic progression is -16, -3, 10,...

We observe that the first term of this progression is $a_1=-16$.

The constant difference is

$d=-3--16\\d=-3+16=13$

The 89th term of an arithmetic sequence is given by:

$a_{89}=a_1+88d$

We substitute the first term and the common difference to obtain:

$a_{89}=-16+88(13)$

We simplify to get:

$a_{89}=-16+1144$

This simplifies to:

$a_{89}=1128$