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andrew-mc [135]
2 years ago
7

Find the 89th term of the arithmetic sequence -16 -3 10

Mathematics
1 answer:
Alekssandra [29.7K]2 years ago
8 0

Answer:

a_{89}=1128

Step-by-step explanation:

The given arithmetic progression is -16, -3, 10,...

We observe that the first term of this progression is a_1=-16.

The constant difference is

d=-3--16\\d=-3+16=13

The 89th term of an arithmetic sequence is given by:

a_{89}=a_1+88d

We substitute the first term and the common difference to obtain:

a_{89}=-16+88(13)

We simplify to get:

a_{89}=-16+1144

This simplifies to:

a_{89}=1128

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