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xenn [34]
2 years ago
14

Sonya currently has an account balance of $1,533.43. Her initial deposit on the account was $962 and i earned 3.3% simple intere

st. How long has Sonya held the account?
Mathematics
1 answer:
Dafna11 [192]2 years ago
6 0

Current account balance of Sonya = $1,533.43.

Initial deposited amount = $962.

Interest earned = Current Balance -Initial deposite = 1,533.43-962= $571.43.

Given interest rate = 3.3% per year.

3.3% could be convert in decimal form as 3.3/100= 0.033.

Let us assume number of years Sonya had account=t years.

Simple interest formula is given by

I=P*R*T, where P is the initial deposited amount, R is the rate of interest, T is the time in years and I is the inetrest earned.

Plugging value of I, P and R in the above formula, we get

571.43 = 962 * 0.033 * t

571.43 = 31.746t

Dividing both sides by 31.746, we get

571.43/31.746 = 31.746t/31.746

t=18 years.

Therefore, Sonya held the account for 18 years.

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Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units. Which statements bes
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Answer:

<h3>Q cuts the diagonal PA into 2 equal halves, since the diagonals of rhombus meet at right angles.</h3><h3>The value of x is 8.</h3>

Step-by-step explanation:

Given that Quadrilateral CAMP below is a rhombus. the length PQ is (x+2) units, and the length of QA is (3x-14) units

From the given Q is the middle point, which cut the diagonal PA into 2 equal halves.

By the definition of rhombus, diagonals meet at right angles.

Implies that PQ = QA

x+2 = 3x - 14

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dividing by 2 on both sides, we will get,

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The line segment \overrightarrow{PA}=\overrightarrow{PQ}+\overrightarrow{QA}

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2 years ago
If on a scale drawing 15 feet are represented by 10 inches then a scale of 1/10 inch represents how many feet
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A scale of \frac{1}{10} inches will represent \frac{3}{20} feet.

Step-by-step explanation:

According to scale drawing;

15 feet = 10 inches

1 inch = \frac{15}{10}=\frac{3}{2}\ feet

A scale of \frac{1}{10} inch will represent;

Multiplying both sides by

\frac{1}{10}*1=\frac{3}{2}*\frac{1}{10}\\\\\frac{1}{10}\ inches = \frac{3}{20}\ feet

A scale of \frac{1}{10} inches will represent \frac{3}{20} feet.

Keywords: fraction, multiplication

Learn more about fractions at:

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  • brainly.com/question/4163549

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Let P and Q be polynomials with positive coefficients. Consider the limit below. lim x→[infinity] P(x) Q(x) (a) Find the limit i
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Answer:

If the limit that you want to find is \lim_{x\to \infty}\dfrac{P(x)}{Q(x)} then you can use the following proof.

Step-by-step explanation:

Let P(x)=a_{n}x^{n}+a_{n-1}x^{n-1}+\cdots+a_{1}x+a_{0} and Q(x)=b_{m}x^{m}+b_{m-1}x^{n-1}+\cdots+b_{1}x+b_{0} be the given polinomials. Then

\dfrac{P(x)}{Q(x)}=\dfrac{x^{n}(a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n})}{x^{m}(b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m})}=x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}

Observe that

\lim_{x\to \infty}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)})+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\dfrac{a_{n}}{b_{m}}

and

\lim_{x\to \infty} x^{n-m}=\begin{cases}0& \text{if}\,\, nm\end{cases}

Then

\lim_{x\to \infty}=\lim_{x\to \infty}x^{n-m}\dfrac{a_{n}+a_{n-1}x^{-1}+a_{n-2}x^{-2}+\cdots +a_{2}x^{-(n-2)}+a_{1}x^{-(n-1)}+a_{0}x^{-n}}{b_{m}+b_{m-1}x^{-1}+b_{n-2}x^{-2}+\cdots+b_{2}x^{-(m-2)}+b_{1}x^{-(m-1)}+b_{0}x^{-m}}=\begin{cases}0 & \text{if}\,\, nm \end{cases}

3 0
2 years ago
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