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hichkok12 [17]
2 years ago
5

Mr and Mrs Smith buy tickets for themselves and their four children.

Mathematics
1 answer:
Aneli [31]2 years ago
4 0
The cost of an adult ticket is £6 more than that of a child ticket, so will be denoted by c+6. Now, we are told that the cost of four child tickets and two adult tickets is £40.50, so we can put this in an equation and solve for c:
(c+6)+(c+6)+c+c+c+c=40.50
6c+12=40.50
6c=28.50
c=4.75
Therefore the cost of a child's ticket (c) is £4.75 and the cost of an adult ticket (c+6) is £10.75.
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James is the manager at an entertainment arena that draws an average 7,000 patrons per event. Each ticket taker can process 350
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Answer:

No. James didn't have enough ticket takers to process the average number of patrons hat usually attend the events.

He need to hire 2 more ticket taker (i.e 20 ticket takers) in order to process the average number of patrons hat usually attend the events.

Step-by-step explanation:

Given:

Average amount of patron per event= 7000

Each ticket taker can process = 350

Number of ticket takers hired = 18

We need to find the whether he hire enough to process the average number of patrons that usually attend the events.

Solution:

We will find the Average amount of patron ticket takers can process.

Now we can say that

Average amount of patron ticket takers can process is equal to Each ticket taker can process multiplied by Number of ticket takers hired.

framing in equation form we get;

Average amount of patron ticket takers can process = 350 \times 18 = 6300\ patrons

Hence With the required hires James cannot fully process the patrons usually attending the event.

To find how many ticket takers required we will divide average number of patrons with  Each ticket taker can process.

framing in equation form we get;

ticket takers required = \frac{7000}{350}=20

hence In order t process the the average number of patrons that usually attend the events James will require 20 ticket takers.

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