we know that
In an Arithmetic Sequence the difference between one term and the next is a constant
This problem is an Arithmetic Sequence
where
the first term is 
and
the common difference is 
In general we can write an Arithmetic Sequence as a rule

where
a1 is the first term
d is the common difference
so

<u>Find the term a7</u>
![an=a1+d*(n-1)\\ \\ a7=23+(-2)*[7-1]\\ \\\\ a7=23-12\\ \\\\ a7=11](https://tex.z-dn.net/?f=%20an%3Da1%2Bd%2A%28n-1%29%5C%5C%20%5C%5C%20%20a7%3D23%2B%28-2%29%2A%5B7-1%5D%5C%5C%20%5C%5C%5C%5C%20a7%3D23-12%5C%5C%20%5C%5C%5C%5C%20%20%20%20a7%3D11%20%20%20%20%20)
therefore
<u>the answer is</u>

Answer:
1. Multiply (2) by 2 to eliminate the x-terms when adding
2. Multiply (2) by 3 to eliminate the y- term
Step-by-step explanation:
Use this system of equations to answer the questions that follow.
4x-9y = 7
-2x+ 3y= 4
what number would you multiply the second equation by in order to eliminate the x-terms when adding the first equation?
4x-9y = 7 (1)
-2x+ 3y= 4 (2)
Multiply (2) by 2 to eliminate the x-terms when adding the first equation
4x-9y = 7
-4x +6y = 8
Adding the equations
4x + (-4x) -9y + 6y = 7 + 8
4x - 4x - 3y = 15
-3y = 15
y = 15/-3
= -5
what number would you multiply the second equation by in order to eliminate the y- term when adding the second equation?
4x-9y = 7 (1)
-2x+ 3y= 4 (2)
Multiply (2) by 3 to eliminate the y- term
4x - 9y = 7
-6x + 9y = 12
Adding the equations
4x + (-6x) -9y + 9y = 7 + 12
4x - 6x = 19
-2x = 19
x = 19/-2
= -9.5
x = -9.5
Answer:
a) the sample size (n) = 156.25≅ 156
Step-by-step explanation:
<u>Step1 </u>:-
Given the two sample sizes are equal so 
Given the standard error (S.E) = 0.04
The standard error of the proportion of the given sample size

Step 2:-
here we assume that the proportion of boys and girls are equally likely
p= 1/2 and q= 1/2


squaring on both sides, we get

on simplification, we get
n= 156.25 ≅ 156
sample size (n) = 156
<u>verification</u>:-
Standard error = 0.04