Alejandro bought $3.50 worth of pencils and erasers at the school store. Pencils cost $0.50 apiece, and erasers cost $0.75 apiec
2 answers:
Answer:
The answer is the option B
Step-by-step explanation:
Let
p------> the number of pencils
e------> the number of erasers
we know that
The total cost of pencils and erasers, is equal to the numbers of pencils multiplied by plus the number of erasers multiplied by
so
------> equation that represent the situation written in standard form
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Answer:
(a) Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = 0.15716
(b) Probability that a standard normal random variable will be between .3 and 3.2 = 0.3814
Step-by-step explanation:
We are given that the population of lengths of aluminum-coated steel sheets is normally distributed with;
Mean, = 30.05 inches and Standard deviation,
= 0.2 inches
Let X = A sheet selected at random from the population
Here, the standard normal formula is ;
Z = ~ N(0,1)
(a) <em>The Probability that a sheet selected at random from the population is between 30.25 and 30.65 inches long = P(30.25 < X < 30.65) </em>
P(30.25 < X < 30.65) = P(X < 30.65) - P(X <= 30.25)
P(X < 30.65) = P( <
) = P(Z < 3) = 1 - P(Z >= 3) = 1 - 0.001425
= 0.9985
P(X <= 30.25) = P( <=
) = P(Z <= 1) = 0.84134
Therefore, P(30.25 < X < 30.65) = 0.9985 - 0.84134 = 0.15716 .
(b)<em> Let Y = Standard Normal Variable is given by N(0,1) </em>
<em> Which means mean of Y = 0 and standard deviation of Y = 1</em>
So, Probability that a standard normal random variable will be between 0.3 and 3.2 = P(0.3 < Y < 3.2) = P(Y < 3.2) - P(Y <= 0.3)
P(Y < 3.2) = P( <
) = P(Z < 3.2) = 1 - P(Z >= 3.2) = 1 - 0.000688
= 0.99931
P(Y <= 0.3) = P( <=
) = P(Z <= 0.3) = 0.61791
Therefore, P(0.3 < Y < 3.2) = 0.99931 - 0.61791 = 0.3814 .
Answer:
<h2>Height (h) =54.6mm</h2>Step-by-step explanation:
Given :
Base (b) = 7.7mm
Area (a) = 210.21mm^2
Height (h) = ?