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1 year ago

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3 + 5.2x= 1 - 2.8x how do I solve this?

1 answer:

MrRa [10]1 year ago

5 0

3+5.2x=1-2.8x

1. 3+5.2x+2.8x=1

2. 5.2x+2.8x=1-3

5.2x+2.8x=1-3

1. 8x=1-3

2. 8x=-2

8x=-2

1. =-(1/4)

Alternative form:

2. x=-0.25

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Answer:

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean 490 mg and variance of 400.

This means that $\mu = 490, \sigma = \sqrt{400} = 20$

What is the probability that a randomly selected pill contains at least 500 mg of minerals?

This is 1 subtracted by the p-value of Z when X = 500. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{500 - 490}{20}$

$Z = 0.5$

$Z = 0.5$ has a p-value of 0.6915.

1 - 0.6915 = 0.3085

0.3085 = 30.85% probability that a randomly selected pill contains at least 500 mg of minerals

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HELP PLEASE The annual salaries of all employees at a financial company are normally distributed with a mean Mu = $34,000 and a

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C

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Mathematically;

z-score = (x- mean)/SD

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Plugging these values into the equation above, we have;

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Let's assume initial population is in 1999

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