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Varvara68 [4.7K]
2 years ago
11

Marshall left home biking at a constant rate of 20 mph. One hour later, it looked like it may rain, so his friend, Brett, set ou

t in his car to pick him up. Brett drove at a constant rate of 60 mph. How many hours will Marshall have been riding his bike by the time Brett catches up to him?
A. 0.5
B. 1.0
C. 1.5
D. 2.0
Mathematics
1 answer:
Alexus [3.1K]2 years ago
6 0
First, we need to find how far ahead Marshall was.  Since he had been biking at 20 mph for one hour, he had gone 20 miles.

Next, we need to find how long it will take Brett to catch up to Marshall.  In order to do this, we need to find how much faster Brett is going than Marshall.  We do this by subtracting Marshall's speed from Brett's speed.

60 - 20 = 40.  So, Brett is catching up to Marshall at 40 mph.  Now, we figure out how long it will take for someone going 40 miles per hour to go 20 miles.  We find this by dividing 40 miles per hour by 20.  This is equal to 1/2 hour.  So, it will take Brett 0.5 hours to catch up to Marshall.  This is the same as A, so A is the correct answer.

We can check our answer by seeing how far Marshall and Brett will have gone.  Marshall will have been biking for 1.5 hours, so we multiply 20 * 1.5 = 30.  Marshall went 30 miles.

Brett drove for .5 hours at 60 mph, so he went 30 miles.  Since Brett and Marshall went the same distance, our answer is correct.
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Answer:

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Step-by-step explanation:

Step 1: Derive the first expression

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where;

a=number of adults

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And total number of people=10

Step 2: Derive the second expression;

Total cost of tickets=(price per child ticket×number of children)+(price per adult ticket×number of adults)

where;

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number of children=c

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replacing;

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24.95 a+15.95 c=186.5....equation 2

Step 3: Combine equation 1 and 2 and solve simultaneously

24.95 a+15.95 c=186.5

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24.95(a+c=10)

(24.95 a-24.95 a)+(15.95 c-24.95 c)=186.5-(24.95×10)

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