After reducing the fraction it becomes equal to 5/12. Let the common element which was cancelled out be x. So we can say the original fraction was

.
The denominator of the fraction is 147 greater than the numerator. We can write it as:
12x = 147 + 5x
12x - 5x = 147
7x = 147
x = 21
So, the numerator of the fraction was 5 x 21 = 105
Denominator of the fraction was 12 x 21 = 252
So our original fraction was
Answer:
dilation
Step-by-step explanation:
did it on edge 2020
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For these lines, let

.

And for these, let

.
Now,

The vertices of

in the x-y plane are (0, 2), (2/3, 10/3), (2, 2), and (4/3, 2/3). Applying

to each of these yields, respectively, (2, 2), (2, 4), (-2, 4), and (-2, 2), which are the vertices of a rectangle whose sides are parallel to the u-v plane.
Combine place value strategy is useful if you try to subtract a number with bigger digits from a number with a smaller digit in the same place... such as now, where 3 is smaller than 9 in the ones place.
Then we can combine two place values: 23 and 19 and subtruct those. 23-19 is 4 (you can just count up from 19 to 23), so you know that the two will give the result of 04, and then you can proceed to the left: 2-1=1.
so the final result will 104.
Answer:
P(t) = 1000e^(0.01155)t
Step-by-step explanation:
Let the population of barangay be expressed according to the exponential formula;
P(t) = P0e^kt
P(t) is the population of the country after t years
P0 is the initial population
t is the time
If barangay has 1000 initially, this means that P0 = 1000
If the population doubles after 60years then;
at t = 60, P(t) = 2P0
Substitute into the formula
2P0 = P0e^k(60)
2 = e^60k
Apply ln to both sides
ln2 = lne^60k
ln2 = 60k
k = ln2/60
k = 0.01155
Substitute k = 0.01155 and P0 into the expression
P(t) = 1000e^(0.01155)t
Hence an exponential model for barangay's population is
P(t) = 1000e^(0.01155)t