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stepan [7]
2 years ago
12

The results of an election are shown in the table below.

Mathematics
1 answer:
Luden [163]2 years ago
5 0

We are given the results of an election:

Candidate Fraction of votes

Johnson = \frac{1}{9}

Smith  = \frac{7}{18}

Dragovic = \frac{1}{2}

Now, we need to find the difference between the fractions of votes received by Dragovic and Johnson.

Therefore, difference is :

\frac{1}{2} - \frac{1}{9}

Taking common denominator of 2 and 9 is 18.

=\frac{1\times9}{2\times 9} - \frac{1\times 2}{9\times 2}

=\frac{9}{18} - \frac{2}{18}

=\frac{9-2}{18}

=\frac{7}{18}

Therefore, the difference between the fractions of votes received by Dragovic and Johnson is \frac{7}{18}.


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Answer:

a)  1/10 x 5/10 = 1/20

b) 1/10 x 5/9 = 1/18

Step-by-step explanation:

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Playing tennis burns energy at a rate of about 25 kJ/min. Cycling burns energy at about 35kJ/min. Hans exercised by playing tenn
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To answer this, you need to make a systems of equations.

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8 0
1 year ago
Which statements are true regarding triangle LMN? Check all that apply.
dimaraw [331]

Answer:

NM = x

LM = x\sqrt{2}

tan (45) = 1

Step-by-step explanation:

Step 1: Pythagoras Theorem

Pythagoras theorem relates the three sides of the triangle in such a way that the sum of the square of base and perpendicular is equal to hypotenuse, such as:

                                        LM^{2} =LN^{2} +NM^{2}

Step 2: Trigonometric Functions

Only for a right angle triangle following three trigonometric relations are valid

                                        sin (\theta) = \frac{opposite}{hypotenuse}

                                        cos (\theta) = \frac{adjacent}{hypotenuse}

                                    tan (\theta)=\frac{sin (\theta)}{cos (\theta)} = \frac{opposite}{adjacent}

Step 3: Verifying all the possible answers

A: Since, LN = x and using tan (45) =1

we can calculate

                                              tan (\theta)= \frac{opposite}{adjacent}

                                           tan (45)= \frac{NM}{x} =1

therefore, NM = x (true)

B: As NM = x therefore it can not be equal to x\sqrt{2\\}.

C: Using Pythagoras Theorem

                                        LM^{2} =LN^{2} +NM^{2}

                                           LM^{2} =x^{2} +x^{2}

                                              LM^{2} =2x^{2}

                                         LM = \sqrt{2x^{2}} = x\sqrt{2}

It can also be proved using trigonometric relation

                                           cos (45) = \frac{x}{LM}

                                            LM = \frac{x}{cos (45)}

As, \frac{1}{cos (45)}= \sqrt{2}

Therefore

                                            LM = x\sqrt{2}

D and E:

Using same approach similar to part A

Since, LN = x and NM = x

we can calculate

                                              tan (\theta)= \frac{opposite}{adjacent}

                                           tan (45)= \frac{x}{x} =1

Therefore, tan (45) = 1  and not equal to \frac{\sqrt{2} }{2}

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