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stepan [7]
2 years ago
12

The results of an election are shown in the table below.

Mathematics
1 answer:
Luden [163]2 years ago
5 0

We are given the results of an election:

Candidate Fraction of votes

Johnson = \frac{1}{9}

Smith  = \frac{7}{18}

Dragovic = \frac{1}{2}

Now, we need to find the difference between the fractions of votes received by Dragovic and Johnson.

Therefore, difference is :

\frac{1}{2} - \frac{1}{9}

Taking common denominator of 2 and 9 is 18.

=\frac{1\times9}{2\times 9} - \frac{1\times 2}{9\times 2}

=\frac{9}{18} - \frac{2}{18}

=\frac{9-2}{18}

=\frac{7}{18}

Therefore, the difference between the fractions of votes received by Dragovic and Johnson is \frac{7}{18}.


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A recipe calls for 1/4 cup of broth. The largest volume-measuring tool that Tabitha has is a teaspoon. She knows that there are
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Answer:

Option b. 12 teaspoons.

Step-by-step explanation:

In the question it given :

1 cup = 16 tablespoons

1 tablespoon = 3 teaspoons

16 tablespoon = 48 teaspoons or 1 cup

A recipe calls for 1/4 cup of broth. Tabitha has only a teaspoon to measure broth.

1 cup broth = 48 teaspoons

1/4 cup broth = 48 × \frac{1}{4} = 12 teaspoons

Tabitha should use 12 teaspoons of broth.

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In the transmission of digital information, the probability that a bit has high, moderate, and low distortion is 0.02, 0.07, and
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Answer:

A. (Table Attached)

B. (See Step 3)

C. 0.06 (See Step 4)

D. NOT independent (See Step 5)

Step-by-step explanation:

<h3 /><h3>STEP 1:</h3>

Name the probabilities:

p₁ = 0.02,   p₂ = 0.07,   p₃ = 0.91

q₁ = 1-p₁ = 0.98 ,   q₂ = 1-p₂ = 0.93 ,   q₃ = 0.09

Let X and Y be the number of bits with high and moderate distortion out of three.

<h3>STEP 2:</h3>

A.

The function will follow multinomial distribution:

f_{XY}(x,y) = P(X=x, Y=y) = \frac{3!}{x!y!(3-x-y)!} (p_1^x)(p_2^y)(p_3^{3-x-y})

Substitute the values and make a table.

TABLE IN ATTACHMENT

<h3>STEP 3:</h3>

B.

We calculate marginal distribution by:

P (X=x)= <em>∑</em> P(X=x,Y=y)

fx(x) can be found by adding all the probabilities in each row for different value of X

For X=0 , ∑P = 0.94157441

For X=1 , ∑P = 0.057624

For X=2 , ∑P = 0.001176

For X=3 , ∑P =0.000008

<h3>STEP 4:</h3><h3>C.</h3>

The mathematic expectation E is the sum of product of each possibility with its probabiity.

E(X)=<em>∑ </em>xP(X=x)

Find E(X):

E(X)= (0*0.9415744)+(1*0.057624)+(2*0.001176)+(3*0.000008)

E(X)=0.06

<h3>STEP 5:</h3>

Condition probability states:

P(A|B)=\frac{P(A,B)}{P(B)}

It can also be written as:

f_{Y|X=1}(y)=\frac{f_{XY}(1,y)}{f_x(1)}

Where f_x(1)\\ = 0.057624

Calculate the quotient:

Y|_{x=1} = 0 ,  f_{Y|_X=1 = 0.862245

Y|_{x=1} = 1 ,  f_{Y|_X=1 = 0.132653

Y|_{x=1} = 2 ,  f_{Y|_X=1 = 0.000510

Y|_{x=1} = 3 ,  f_{Y|_X=1 = 0

Find the dependency:

f_{XY}(y)=f_X(x)f_Y(y)

We found that

f_{Y|_X=1 = 0.862245

Calculate f_Y(1) from summing the column from the table

f_Y(1)=0.17428341+0.007644+0.000084\\f_Y(1)=0.18201141

Which are not equal.

Conclusion:

X and Y are NOT Independent

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