Whether dividing constant terms or polynomials, we always have definitive terms when it comes to division. Suppose we say, 10x divided by 2. The dividend is the 10x and the divisor is the 2. In other words, the dividend is the number to be divided by the divisor, to obtain the answer called the quotient.
When dividing polynomials, your main goal is to be able to divide the dividend evenly into the <em>divisor</em>. For example, we divide x²+2x+1 by x+1. The first thing you're going to focus is, what term will completely divide the first term of the polynomial? That would be x. Why? Because when you multiply x with x+1, the product is x²+x. When you subtract this from the polynomial, the x² will cancel out. All you have to do is subtract x from 2x, yielding x. Then, you carry down the last term of the equation: +1. You do the steps again. The term that will completely divide x+1 by x+1 is 1. When you subtract the two, you will come up with zero. That means there is no remainder. The polynomial is divisible by the divisor.
x + 1
------------------------------------
x+1| x²+2x+1
- x²+x
----------------------
x +1
- x +
------------
0
Answer:
A) 3.5
B) 1.6202
Step-by-step explanation:
In binomial distribution,
E(X) = np and Var(X) = npq while
SD (X) = √(npq)
Where n is number of cards drawn
p is probability of getting one particular shape
q = 1-p
So from the question, n = 14
p = 13/52 = 1/4
q = 1-(1/4) = 3/4
So;
A) E(x) = np = 14 x 1/4 = 3.5
B) SD (X) = √(npq) = √(14 x 1/4 x 3/4) = √(42/16) = √2.625 = 1.6202
Answer:
F(x) = 2/3x + 3
Step-by-step explanation:
I found this out by first starting off with the equation, f(x) = mx + b. (b is the y intercept, m is the slope.) The y intercept, where the line passes through the y axis, is 3. (f(x) = mx + 3) Now, look at rise over run, and see that the slope is 2/3, since for every one it goes over, it goes up 2/3. your final equation is f(x) = 2/3x + 3
Answer:
A
Step-by-step explanation:
6.99 - 6 = 0.99
8 - 6.99 = 1.01
1.01>0.99
So it's A
Brainliest???
Ho ho ho, lets get this party started
ok so I'm just really excited to use this stuff that I just learned
so
multiplicites
if a root or zero has an even multilicity, the graph bounces on that root
if the root or zero has an odd multiplicty, the graph goes through that root
so
roots are
-1
2
4
multiplicty is how many times it repeats
2 has even multiplity
we just do 2 is odd and 1 is even so
for roots, r1 and r2, the facotrs would be
(x-r1)(x-r2)
so
(x-(-1))^1(x-2)^2(x-4)
(x+1)(x-2)^2(x-4)
this is a 4th degre equaton
normally, it is goig from top right to top left
it is upside down
theefor it has negative leading coefient
y=-k(x+1)(x-4)(x-2)^2
