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2 years ago

Marcus solved this problem and found that 190% of 20 is 380. Is he correct? Explain why or why not.

Mathematics

2 answers:

ruslelena [56]2 years ago

5 0

Answer:

Step-by-step explanation:

because, 190% as a decimal is 1.9. So 1.9 times 20 is 38. Not 380.

Please mark me brainliest

tatiyna1 year ago

5 0

Answer: No, Marcus is not correct. He converted the percent to a decimal correctly and he multiplied correctly, but he put the decimal in the wrong place in the answer. There should be two decimal places in the answer, so the answer should be 38.

Step-by-step explanation: because I said so also I took the quiz.

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Please help. Find the length of the side labeled x. Round intermediate values to the nearest thousandth. Use the rounded value

Vaselesa [24]

19)18.7 20)7.9
21)13.3 22)102.4

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1 year ago

Read 2 more answers

A graph in which the frequency for each category of a quantitative variable is represented as a vertical column that touches the

Arturiano [62]

Answer:

Histogram.

Step-by-step explanation:

Such a Graph is called Histogram.

A histogram can be defined as a visual representation of data in form of bars of different heights. In histogram, each and every bar groups numbers into ranges. The greater the height of the bar, the larger the data falls into its range. It basically represents shape and spread of continuous data sample.

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1 year ago

4. Hydrocarbons in the cab of an automobile were measured during trips on the New Jersey Turnpike and trips through the Lincoln

pochemuha

Answer:

No these these result do not differ at 95% confidence level

Step-by-step explanation:

From the question we are told that

The first concentrations is $c _1= 30.0 \ g/m^3$

The second concentrations is $c _2 = 52.9 \ g/m^3$

The first sample size is $n_1 = 32$

The second sample size is $n_2 = 32$

The first standard deviation is $\sigma_1 = 30.0$

The first standard deviation is $\sigma_1 = 29.0$

The mean for Turnpike is $\= x _1 = \frac{c_1}{n} = \frac{31.4}{32} = 0.98125$

The mean for Tunnel is $\= x _2 = \frac{c_2}{n} = \frac{52.9}{32} = 1.6531$

The null hypothesis is $H_o : \mu _1 - \mu_2 = 0$

The alternative hypothesis is $H_a : \mu _1 - \mu_2 \ne 0$

Generally the test statistics is mathematically represented as

$t = \frac{\= x_1 - \= x_2}{ \sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} }}$

$t = \frac{0.98125 - 1.6531}{ \sqrt{\frac{30^2}{32} +\frac{29^2}{32} }}$

$t = - 0.0899$

Generally the degree of freedom is mathematically represented as

$df = 32+ 32 - 2$

$df = 62$

The significance $\alpha$ is evaluated as

$\alpha = (C - 100 )\%$

=> $\alpha = (95 - 100 )\%$

=> $\alpha =0.05$

The critical value is evaluated as

$t_c = 2 * t_{0.05 , 62}$

From the student t- distribution table

$t_{0.05, 62} = 1.67$

$t_c = 2 * 1.67$

=> $t_c = 3.34$

given that

$t_c > t$ we fail to reject the null hypothesis so this mean that the result do not differ

6 0

1 year ago

the table shows the number of minutes Tim has for lunch and study hall. he calculates that these two periods account for 18% of

EleoNora [17]

Tim spends 500 minutes at the school.

Step-by-step explanation:

Given,

Time for lunch = 45 minutes

Time for study hall = 45 minutes

Total = 45+45 = 90 minutes

This represents 18% of the total minutes Tim spend at school.

Let,

x be the total minutes Tim spend at school.

18% of x = 90 minutes

$\frac{18}{100}x=90\\\\0.18x=90$

Dividing both sides by 0.18

$\frac{0.18x}{0.18}=\frac{90}{0.18}\\x=500$

Tim spends 500 minutes at the school.

Keywords: percentage, division

Learn more about division at:

#LearnwithBrainly

5 0

2 years ago

Suppose we have a group of 10 light users and 10 heavy users. what is the probability that exactly 3 of the 20 users are hiv pos

dmitriy555 [2]

Answer: The answer is 30%.

Step-by-step explanation: Given that there is a group of 10 light users and 10 heavy users. We are to find the probability that exactly 3 of the 20 users are HIV positive.

We have the following four possible cases -

(i) All 3 are light users.

(ii) 1 is a light user and 2 are heavy users.

(iii) 2 are light users and 1 is a heavy user.

(iv) All 3 are heavy user.

Since there is a 45% chance of a light user to be HIV positive and 55% chance of a heavy user to be HIV positive, so the required probability is given by

$p\\\\=\dfrac{3\times 0.45+1\times 0.45+2\times 0.55+2\times 0.45+1\times 0.55+3\times 0.55}{20}\\\\=\dfrac{6}{20}\\\\=0.3\\\\=30\%.$

Thus, the probability is 30.

4 0

1 year ago