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Sholpan [36]
2 years ago
15

If you were to plot y versus m using the equation y = (g/k) m yo, how would you calculate the value for k?

Mathematics
1 answer:
Zanzabum2 years ago
3 0

Equation is given as;

y = (g/k) yo

To find the value of “k”, divide both sides of the equation with yo;

y/yo = (g/k)yo/yo

it implies that;

y/yo = (g/k)

Now following steps will obtain the value of “k” as;

ky/yo = g

ky = gyo

<span>k = gy0/y </span>

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Pleasee! Which expression is equivalent to the given expression? Assume the denominator does not equal zero.
Ilia_Sergeevich [38]

Answer:

A. 2y^4 over x^2

Step-by-step explanation:

4x^4y^6 ÷ 7x^8y^2

First, you will find the GCF of the equation which is: 7x^4y^2 .

Then, you will divide both of the equation by the GCF which will become:

14x^4y^6 ÷ 7x^4y^2 = 2y^4

7x^8y^2 ÷ 7x^4y^2 = x^2

Hence, the final answer is 2y^4 over x^2

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2 years ago
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An oblique rectangular prism with a square base has a volume of 539 cubic units. The edges of the prism measure 7 by 7 by 14 uni
kozerog [31]
The answer is 3 units
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the volume of a cone is 3πx3 cubic units and its height is x units. which expression represents the radius of the cone’s base, i
iVinArrow [24]
The volume given is 3Pi(x^3) and the radius is x. The formula for the volume of a cone is V= [1/3]Pi(r^2)*height => [1/3]Pi (r^2) x = 3Pi(x^3) => (r^2)x = 3*3(x^3) => (r^2)x = 9(x^3) => (r^2) = 9x^2 => r = sqrt[9x^2] = 3x. <span>Answer: r = 3x</span>
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2 years ago
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Which graph matches the equation y+3=2(x+3)?
Vlad1618 [11]

Answer:

The graph that includes points (-3,-3) and (0,3)

Step-by-step explanation:

In the pictures attached, the options are shown.

The equation:

y+3=2(x+3)

has the point-slope form, which is:

y-y₁=m(x-x₁)

where (x₁, y₁) is a point on the line and <em>m</em> is its slope. This means that (-3,-3) is on the line. To know the y-intercept of the line, we have to replace x = 0 into the equation, as follows:

y+3=2(0+3)

y+3 = 6

y = 6 - 3

y = 3

Then, point (0, 3) is on the line.

8 0
2 years ago
A 92.0 kg football player at 6.50 m/s North collides with an 85.0 kg football player running at 6.00 m/s south. The 92.0 kg foot
s2008m [1.1K]

Answer:

-1.13 m/s

Step-by-step explanation:

Parameters given:

Mass of first footballer, M = 92 kg

Initial velocity of first footballer, U = 6.5 m/s (taking North to be the +ve y axis)

Mass of second footballer, m = 85 kg

Initial velocity of second footballer, u = -6.0 m/s (taking South to be the -ve y axis)

Final velocity of first footballer, V = 2.0 m/s

We need to find the final velocity of the second football (v)

Applying the principle of conservation of momentum, we have that, in a system:

Total Initial Momentum = Total Final Momentum

(M * U) + (m * u) = (M * V) + (m * v)

(92 * 6.5) + (85 * -6) = (92 * 2) + (85 * v)

598 - 510 = 184 + 85v

88 = 184 + 85v

88 - 184 = 85v

-96 = 85v

=> v = -96 / 85

v = -1.13 m/s

The final velocity of the 85 kg player is -1.13 m/s i.e 1.13 m/s South

5 0
2 years ago
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