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Contact [7]
2 years ago
6

Juanita wants to perform row operations on the augmented matrix for the system below (See pictures). Which matrix should Juanita

use to perform the operations?

Mathematics
1 answer:
Artist 52 [7]2 years ago
5 0

Answer:

The second option

Step-by-step explanation:

The given system of equation is

x+2y=3

-x+y+z=2

y-2z=-3

The augment matrix is obtained by combining the coefficient matrix with the constant matrix to obtain;

\left[\begin{array}{cccc}1&2&0&|3\\-1&1&1&|2\\0&1&-2&|-3\end{array}\right]

Note that the absence of z, in the first equation means its coefficient is zero. The same thing applies to x in the last equation.

The correct choice is the second option.

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According to a "how to stop bullying" Web site, 15% of students report experiencing bullying one to three times within the most
AlekseyPX

Answer:

His 95% confidence interval is (0.065, 0.155).

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

n = 186, \pi = 0.11

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

The lower limit of this interval is:

\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 - 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.065

The upper limit of this interval is:

\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.11 + 1.96\sqrt{\frac{0.11*0.89}{186}} = 0.155

His 95% confidence interval is (0.065, 0.155).

4 0
2 years ago
The height of seaweed of all plants in a body of water are normally distributed with a mean of 10 cm and a standard deviation of
Degger [83]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: height of seaweed.

X~N(μ;σ²)

μ= 10 cm

σ= 2 cm

You have to find the value of the variable X that separates the bottom 0.30 of the distribution from the top 0.70

P(X≤x)= 0.30

P(X≥x)= 0.70

Using the standard normal distribution you have to find the value of Z that separates the bottom 0.30 from the top 0.70 and then using the formula Z= (X-μ)/σ translate the Z value to the corresponding X value.

P(Z≤z)= 0.30

In the body of the table look for the probability of 0.30 and reach the margins to form the Z value. The mean of the distribution is "0" so below 50% of the distribution you'll find negative values.

z= -0.52

Now you have to clear the value of X:

Z= (X-μ)/σ

Z*σ= X-μ

X= (Z*σ)+μ

X= (-0.52*2)+10= 8.96

The value of seaweed height that divides the bottom 30%  from the top 70% is 8.96 cm

I hope this helps!

7 0
2 years ago
If ∆ABC and ∆GEF are congruent, the value of x is___? and the value of y is ___?
attashe74 [19]

<u>Answer-</u>

<em>The value of y is </em><em>6 units</em><em>.</em>

<u>Solution-</u>

Given ∆ABC ≅ ∆GEF

If two triangles are congruent, then the corresponding sides are also congruent.

So,

EF = BC, GF = AC

Putting the values,

\Rightarrow x-y=4 --------------1

\Rightarrow x-8=2

\Rightarrow x=10 --------------------2

Putting the values of x in equation 1,

\Rightarrow 10-y=4

\Rightarrow y=10-4=6

Therefore, the value of y is 6 units.

7 0
2 years ago
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You notice you are growing awfully fast lately. You have been growing at a rate of 3 inches per year. If you are 5 feet tall now
Cerrena [4.2K]

Answer:

4 years

Step-by-step explanation:

FYI this sounds like a personal problem

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2 years ago
A survey finds that 40% of students ride in a car to school. Eri would like to estimate the probability that if 3 students were
Butoxors [25]
The answer is 0.60 I know cause I took the test
3 0
2 years ago
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