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Ludmilka [50]
1 year ago
14

What percent of 84 is 12?

Mathematics
2 answers:
lozanna [386]1 year ago
6 0
So here is what we have

12 is what we need

out of the 84 we have

so...

12/84= .1428571429

and lets check our work

.1428571429 X 84 = 12

now lets convert it to a percent

.1428571429 X 100 = 14.28571429%

so the answer is 

14.28571429%
Doss [256]1 year ago
4 0
12 divided by 84=0.1428. Now 0.1428 times 100% 0.1428X100= 14.28 round up so answer is 14.3%
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sweet [91]

We use the z statistic:

z = (x – u) / s

 

But first let us calculate the standard deviation s, sample x and mean u.

s = sqrt (n p q)

s = sqrt (112 * 0.77 * (1 – 0.77))

s = 4.45

 

x = 0.81 * 112 = 90.72

 

u = 0.77 * 112 = 86.24

 

So the z score is:

z = (90.72 – 86.24) / 4.45

z = 1.00

 

From the standard tables, the P value at z = 1.00 using right tailed test is:

<span>P = 0.1587 = 15.87%</span>

7 0
1 year ago
A local pizzeria offers 15 toppings for their pizzas and you can choose any 3 of them for one fixed price. How many different ty
Shtirlitz [24]

Answer:

  455 or 680, depending

Step-by-step explanation:

If we assume the three choices are different, then there are ...

  15C3 = 15·14·13/(3·2·1) = 35·13 = 455

ways to make the pizza.

___

If two or three of the topping choices can be the same, then there are an additional ...

  2(15C2) +15C1 = 2·105 +15 = 225

ways to make the pizza, for a total of ...

  455 + 225 = 680

different types of pizza.

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There is a factor of 2 attached to the number of choices of 2 toppings, because you can have double anchovies and tomato, or double tomato and anchovies, for example, when your choice of two toppings is anchovies and tomato.

_____

nCk = n!/(k!(n-k)!)

6 0
2 years ago
What is the unit rate of 3 accidents in 12 months
Wewaii [24]
Simplify 3 to 12 Divide 3 1 to 4 So the answer is 1 car accident in 4 month ~JZ Hope it helps you out there
7 0
1 year ago
Read 3 more answers
An inspector checks 98 cell phones and finds that 2 of them are defective. A company has 850 of these phones. How many of the co
jekas [21]

Answer:

17

Step-by-step explanation:

As 2 phones are defective from a group of 98 that were checked, you can determine a percentage:

2/98= 2%

This indicates that 2% of the phones are likely to be defective and because of that you can find 2% of 850:

850*2%= 17

According to this, 17 phones are likely to be defective.

3 0
2 years ago
Formulate the indicated conclusion in nontechnical terms. Be sure to address the original claim. The foundation chair for a hosp
slavikrds [6]

Answer:

For this case we want to test if the mean number of filled overnight beds is over​ 523. If X represent our random variable "number of filled overnight beds", the system of hypothesis are:

Null Hypothesis: \mu \leq 523

Alternative hypothesis: \mu > 523

And for this case after conduct the test is FAIL to reject the null hypothesis. So then we can conclude that the claim that the number of filled overnight beds is over​ 523 is not statistically supported

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".  

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

For this case we want to test if the mean number of filled overnight beds is over​ 523. If X represent our random variable "number of filled overnight beds", the system of hypothesis are:

Null Hypothesis: \mu \leq 523

Alternative hypothesis: \mu > 523

And for this case after conduct the test is FAIL to reject the null hypothesis. So then we can conclude that the claim that the number of filled overnight beds is over​ 523 is not statistically supported

6 0
1 year ago
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