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Irina-Kira [14]
2 years ago
9

1. Janna works at a lab with a huge circular particle accelerator. It has a radius of 4 kilometers. What is the accelerator's di

ameter?
2. KC wants to know the area of the portion with a lot of cheese. The radius of the pizza is 9 inches and the intercepted arc of the pizza with lot of cheese measures 140°. What will be the area of the shaded sector?

3. From the main entrance of the park, there are two pathways where visitors can walk along going to the circular garden. The pathways are both tangent to the garden whose center is 40m away from the main entrance. If the area of the garden is about 706.5 m2, how long is each pathway?

pakisagot po ty!! ​
Mathematics
1 answer:
blsea [12.9K]2 years ago
5 0

Answer:

1. diameter=8 kilometres

2. area=98.96 inches

3. 37m

Step-by-step explanation:

1. diameter= 2*radius

2. area of sector=θ out of 360*πr^{2} where θ is the angle

3. area of garden=πr^{2}

        706.5=πr^{2}

     r^{2}=706.5/π

        = 225(nearest whole)

     r=\sqrt{225}=15m

we now use Pythagoras theorem to find length of each pathway

40^{2} =15^{2} +x^{2}

1600=225+x^{2}

x^{2}=1600-225=1375

x=\sqrt{1375}=37 m (to nearest whole)

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Answer:

a) P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

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P(-1.25

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Part a

Let X the random variable that represent the variable of interest of a population, and for this case we know the distribution for X is given by:

X \sim N(5,1.2)  

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We are interested on this probability

P(X>3.5)

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X>3.5)=P(\frac{X-\mu}{\sigma}>\frac{3.5-\mu}{\sigma})=P(Z>\frac{3.5-5}{1.2})=P(z>-1.25)

And we can find this probability using the complement rule:

P(z>-1.25)=1-P(z

Part b

We are interested on this probability

P(X

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(X

And we can find this probability uing the normal standard table:

P(z

Part c

P(3.5

And we can find this probability with this difference:

P(-1.25

And in order to find these probabilities we can use tables for the normal standard distribution, excel or a calculator.  

P(-1.25

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