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➷ final = original x multiplier^n
n is the number of years
Substitute in the values:
final = 20,000 x 0.875^11
final = 4603.8225
The answer would be $4603.82
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Okay so since it is 32 cents, it will be 0.32
You need to find the number of pounds
So, do 848/0.32
You get 2650
Charmaine purchased 2,650 pounds of rocks
hope this helps:)
Answer:
The standard deviation of car age is 2.17 years.
Step-by-step explanation:
The Empirical Rule states that, for a normally distributed random variable:
68% of the measures are within 1 standard deviation of the mean.
95% of the measures are within 2 standard deviation of the mean.
99.7% of the measures are within 3 standard deviations of the mean.
In this problem, we have that:
Mean = 7.5
(a) If 99.7% of the ages are between 1 year and 14 years, what is the standard deviation of car age?
This means that 1 is 3 standard deviations below the mean and 14 is 3 standard deviations above the mean.
So

I want to find 



The standard deviation of car age is 2.17 years.
Answer:
He runs 2/3 mile in 8 mins, he runs one mile in 12 mins