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Serhud [2]
2 years ago
12

A group of 55 football players were polled about which synthetic grass they like to play on, Chemstrand or Chemgrass. The data f

rom the survey is shown in the Venn diagram. Use the Venn diagram to find the missing values in the frequency table. What are the values of x, y, and z?
Mathematics
2 answers:
SVETLANKA909090 [29]2 years ago
8 0

Answer:

D

Step-by-step explanation:

Got it right, Edge2020.

cricket20 [7]2 years ago
6 0
From the Venn diagram: 15 players like Chemstrand, 17 players like Chemgrass, 13 players like both Chemstrand and Chemgrass while 10 players like neither Chemstrand nor Chemgrass.

The missing values in the frequency table are x - representing the number of players that like both Chemstrand and Chemgrass, y - representing the number of players that like Chemgrass but do not like Chemstrand and z - representing the number of players likes Chemstrand but do not like Chemgrass.

The number of players that like both Chemstrand and Chemgrass is 13. The number of players that like Chemgrass but do not like Chemstrand is 17. The number of players likes Chemstrand but do not like Chemgrass is 15.

Therefore, x = 13, y = 17 and z = 15
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You drive 30 miles due east in a half hour. Then, you turn left and drive 30 miles north in 1 hour. What are your average speed
garri49 [273]
Original position: P1=(0,0)
<span>You drive 30 miles due east in a half hour: x=+30 miles, t1=1/2 hour=0.5 hours
</span><span>Then, you turn left and drive 30 miles north in 1 hour: y=+30 miles, t2=1 hour
Rectangular coordinates of final position: P2=(x,y)→P2=(30,30)
Total time: t=t1+t2=0.5 hours+1 hour→t=1.5 hours

Average speed: S ave=d/t
Total distance: d=x+y=30 miles+30 miles→d=60 miles
S ave = 60 miles / (1.5 hours)
S ave = 40 miles/hour

Velocity is a vector, the magnitude of this vector is the magnitude of the vector of change of position dividing by the total time t
The vector of change of position: s=P1-P2=(30,30)-(0,0)=(30-0,30-0)→
s=(30,30) 
Magnitude of vector s=sqrt[30^2+30^2]=sqrt[30^2*2]=sqrt[30^2]*sqrt(2)
Magnitude of vector s=30*sqrt(2) miles

Magnitude of velocity vector = Magnitud of vector s / t
Magnitude of velocity vector = [30*sqrt(2) miles] / (1.5 hours)
Magnitude of velocity vector = 20*sqrt(2) miles / hour
Magnitude of velocity vector=20*1.4142 miles / hour
Magnitude of velocity vector=28.284 miles/hour

Polar coordinates of your position=(r, theta)
r=Magnitude of vector s=30*sqrt(2) miles
theta=tan^(-1) (y/x) = tan^(-1) [(30 miles) / (30 miles)]
theta=tan^(-1) (1)→theta=45°=Pi/4 (Pi=3.1416)
Polar coordinates of your position: ( 30*sqrt(2) miles, 45°)
Polar coordinate of your position: ( 30*sqrt(2) miles, Pi/4 )

Answers:
Average speed: 40 miles / hour
Velocity: 20*sqrt(2) miles / hour = 28.284 miles / hour
Rectangular coordinates of your position = (30,30)
Polar coordinates of your position=(30*sqrt(2) miles,45°)
Polar coordinates of your position=(30*sqrt(2) miles,Pi/4)</span>
4 0
2 years ago
Ten young adults living in California rated the taste of a newly developed sushi pizza topped with tuna, rice, and kelp on a sca
timurjin [86]

Answer: For California: μ = 33.1; σ² = 1120.50; Range = 32;

For Iowa: μ = 24.5; σ² = 32.73; Range = 19

Step-by-step explanation:

Mean is the average of a population or a sample. It is defined as

μ = ∑x / n, where

x is each number of the set;

n is the total individuals in the sample.

Calculating the <u>Mean</u> for sample of taste of pizza in <u>California</u>:

μ₁ = \frac{34+39+40+46+33+31+34+14+15+45}{10} = 33.1

Calculating the <u>Mean</u> for the sample in Iowa:

μ₂ = \frac{28+25+35+16+25+29+24+26+17+20}{10} = 24.5

Variance measures how far the number in the set is from the mean. Its formula is

σ² = (∑x-μ)² / n -1

which means to find the variance, you have to get the difference between the number and the mean, square the result, add all of them and then divide by (n-1) individuals.

The <u>Variance</u> for the sample in <u>California</u> is

σ² = \frac{(34 - 33.1)^{2}+(39-33.1)^{2}+(40-33.1)^{2}+(46-33.1)^{2}+(33-33.1)^{2}+(34-33.1)^{2}+(14-33.1)^{2}+(15-33.1)^{2}+(45-33.1)^{2}}{9}σ² = 120.50

The <u>Variance</u> for the sample in <u>Iowa</u> is

σ² = 32.73

Range is the difference between the highest and the lowest number of the set: range = highest - lowest

For the sample in <u>California</u>, the <u>Range</u> is

range = 46 - 14 = 32

For the sample in Iowa:

range = 35 - 16 = 19

For California:

  • Mean = 33.1;
  • Variance = 120.50;
  • Range = 32;

For Iowa:

  • Mean = 24.5;
  • Variance = 32.73;
  • Range = 19;

<u />

6 0
2 years ago
What is true about the solution of StartFraction x squared Over 2 x minus 6 EndFraction = StartFraction 9 Over 6 x minus 18 EndF
Lady bird [3.3K]

Answer:

x=\pm\sqrt{3}  and they are actual solutions

Step-by-step explanation:

we have

\frac{x^2}{2x-6}=\frac{9}{6x-18}

Factor the denominators both sides

\frac{x^2}{2(x-3)}=\frac{9}{6(x-3)}

Simplify

\frac{x^2}{2}=\frac{9}{6}

x^2=\frac{18}{6}

x=\pm\sqrt{3}

<u><em>Verify</em></u>

1) For x=\sqrt{3}

\frac{\sqrt{3}^2}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}

\frac{3}{2(\sqrt{3}-3)}=\frac{9}{6(\sqrt{3}-3)}

18=18 ---> is true

therefore

x=\sqrt{3} ----> is an actual solution

2) For x=-\sqrt{3}

\frac{-\sqrt{3}^2}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}

\frac{3}{2(-\sqrt{3}-3)}=\frac{9}{6(-\sqrt{3}-3)}

18=18 ---> is true

therefore

x=-\sqrt{3}  ----> is an actual solution

therefore

3 0
2 years ago
Read 2 more answers
In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. Of the students who have a dog as a pet also have cat as a pet.
Travka [436]

Answer:

This problem is incomplete, we do not know the fraction of the students that have a dog and also have a cat. Suppose we write the problem as:

"In Mrs.Hu's classroom, 4/5 of the students have a dog as a pet. X of the students who have a dog as a pet also have cat as a pet. If there are 45 students in her class, how many have both a dog and a cat as pets?"

Where X must be a positive number smaller than one, now we can solve it:

we know that in the class we have 45 students, and 4/5 of those students have dogs, so the number of students that have a dog as a pet is:

N = 45*(4/5) = 36

And we know that X of those 36 students also have a cat, so the number of students that have a dog and a cat is:

M = 36*X

now, we do not have, suppose that the value of X is 1/2 ("1/2 of the students who have a dog also have a cat")

M = 36*(1/2) = 18

So you can replace the value of X in the equation and find the number of students that have a dog and a cat as pets.

5 0
2 years ago
Read 2 more answers
Cabs use a valuable commodity—gas! Research average gas prices from 2005–
Doss [256]

Answer:

a

Step-by-step explanation:


6 0
2 years ago
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