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Serhud [2]
2 years ago
12

A group of 55 football players were polled about which synthetic grass they like to play on, Chemstrand or Chemgrass. The data f

rom the survey is shown in the Venn diagram. Use the Venn diagram to find the missing values in the frequency table. What are the values of x, y, and z?
Mathematics
2 answers:
SVETLANKA909090 [29]2 years ago
8 0

Answer:

D

Step-by-step explanation:

Got it right, Edge2020.

cricket20 [7]2 years ago
6 0
From the Venn diagram: 15 players like Chemstrand, 17 players like Chemgrass, 13 players like both Chemstrand and Chemgrass while 10 players like neither Chemstrand nor Chemgrass.

The missing values in the frequency table are x - representing the number of players that like both Chemstrand and Chemgrass, y - representing the number of players that like Chemgrass but do not like Chemstrand and z - representing the number of players likes Chemstrand but do not like Chemgrass.

The number of players that like both Chemstrand and Chemgrass is 13. The number of players that like Chemgrass but do not like Chemstrand is 17. The number of players likes Chemstrand but do not like Chemgrass is 15.

Therefore, x = 13, y = 17 and z = 15
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Answer: 5 units

Step-by-step explanation:

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Kyle is converting 13°F to °C. His work is shown. Is Kyle's answer correct? If not, find his mistake and determine the correct a
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<span><span>No, Kyle's answer is incorrect because he added 32 instead of subtracting. The correct answer is −11°C.</span></span>
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The dotplot shows the heights of 25 students in Mrs. Navard’s statistics class.
Zolol [24]

Answer:

A)Percentile for Lynette, the student who is 65 in. tall is 36th

B) Asher is 22 inches tall.

Step-by-step explanation:

Percentile : It is a measure used in statistics indicating the value below which a given percentage of observations in a group of observations falls

A) Find the Percentile for Lynette, the student who is 65 in. tall.

No. of students below 65 inch =9

So, Percentage of data below 65 inch =\frac{9}{25} \times 100 = 36 \%

So, Percentile for Lynette, the student who is 65 in. tall is 36th

B)Ashers height is at the 88th percentile of the distribution. Interpret this value in context. How tall is Asher

88=\frac{x}{25} \times 100 \\\frac{2200}{100}=x

22=x

So, No. of students below or st 88th percentile = 22

So, Asher is 22 inches tall.

4 0
2 years ago
A railroad crew can lay 7 miles of track each day. They need to lay 203 miles of track. The length, L (in miles), that is left t
swat32

Answer:

It will take 29 days to lay the track

After 18 days the crew still has 77 miles of track left to lay

Step-by-step explanation:

203÷7

=29 days

L= 203 - 7(18)

L= 203 - 126

L= 77

7 0
2 years ago
A bank gets an average of 12 customers per hour. Assume the variable follows a Poisson distribution. Find the probability that t
Alina [70]

Answer:

75.76% probability that there will be 10 or more customers at this bank in one hour.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given interval.

A bank gets an average of 12 customers per hour.

This means that \mu = 12

Find the probability that there will be 10 or more customers at this bank in one hour.

Either there are less than 10 customers, or there are 10 or more. The sum of the probabilities of these events is 1. Then

P(X < 10) + P(X \geq 10) = 1

We want P(X \geq 10)

Then

P(X \geq 10) = 1 - P(X < 10)

In which

P(X < 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9)

So

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-12}*12^{0}}{(0)!} \approx 0

P(X = 1) = \frac{e^{-12}*12^{1}}{(1)!} = 0.0001

P(X = 2) = \frac{e^{-12}*12^{2}}{(2)!} = 0.0004

P(X = 3) = \frac{e^{-12}*12^{3}}{(3)!} = 0.0018

P(X = 4) = \frac{e^{-12}*12^{4}}{(4)!} = 0.0053

P(X = 5) = \frac{e^{-12}*12^{5}}{(5)!} = 0.0127

P(X = 6) = \frac{e^{-12}*12^{6}}{(6)!} = 0.0255

P(X = 7) = \frac{e^{-12}*12^{7}}{(7)!} = 0.0437

P(X = 8) = \frac{e^{-12}*12^{8}}{(8)!} = 0.0655

P(X = 9) = \frac{e^{-12}*12^{9}}{(9)!} = 0.0874

P(X < 10) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) + P(X = 7) + P(X = 8) + P(X = 9) = 0 + 0.0001 + 0.0004 + 0.0018 + 0.0053 + 0.0127 + 0.0255 + 0.0437 + 0.0655 + 0.0874 = 0.2424

Then

P(X \geq 10) = 1 - P(X < 10) = 1 - 0.2424 = 0.7576

75.76% probability that there will be 10 or more customers at this bank in one hour.

3 0
2 years ago
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