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maw [93]
2 years ago
15

Emily convinced her mom to buy a giant box of her favorite cereal. Her mom doesn't think the box will fit on their shelf. The vo

lume of the box is 10{,}00010,00010, comma, 000 cm^3 3 cubed. The base of the box is 252525 cm by 101010 cm
Mathematics
1 answer:
Mashcka [7]2 years ago
8 0

Complete question:

Emily convinced her mom to buy a giant box of her favorite cereal. Her mom doesn't think the box will fit on their shelf. The volume of the box is 10,000 cm^3 cubed. The base of the box is 25cm by 10cm.

How tall is the box of cereal?

Answer: 40cm

Step-by-step explanation:

Given the following :

Volume = 10,000cm^3

Base of box = 25cm by 10cm,

Base of box = Length × width

Therefore:

Length = 25cm, Width = 10cm

Volume = Lengh × Width × Height

10,000cm^3 = 25cm × 10cm × Height

10,000cm^3 = 250cm^2 × Height

Height = 10,000cm^3 ÷ 250cm^2

Height = 40cm

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Dennis_Churaev [7]

Answer:

Margin of error at 90% is 0.024

Margin of error at 99% is 0.037

Step-by-step explanation:

Sample size = 1076

A poll found that 64% of a random sample of 1076 adults said they believe in ghosts.

So, No. of adults said they believe ghosts = \frac{64}{100} \times 1076=688.64\sim 688

So, x = 688

n = 1076

\widehat{p} = \frac{x}{n}

\widehat{p} = \frac{688}{1076}

\widehat{p} = 0.639

ME=z \times \sqrt{\frac{\widehat{p}(1-\widehat{p})}{n}}

z at 90% confidence is 1.64

ME=1.64 \times \sqrt{\frac{0.639(1-0.639)}{1076}}

ME=0.024

So, margin of error at 90% is 0.024

Find the margin of error needed to be 99% confident.

z at 99% confidence is 2.58

ME=2.58 \times \sqrt{\frac{0.639(1-0.639)}{1076}}

ME=0.024

So, margin of error at 99% is 0.037

5 0
2 years ago
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