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2 years ago

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Emily convinced her mom to buy a giant box of her favorite cereal. Her mom doesn't think the box will fit on their shelf. The vo

lume of the box is 10{,}00010,00010, comma, 000 cm^3 3 cubed. The base of the box is 252525 cm by 101010 cm

1 answer:

Mashcka [7]2 years ago

8 0

Complete question:

Emily convinced her mom to buy a giant box of her favorite cereal. Her mom doesn't think the box will fit on their shelf. The volume of the box is 10,000 cm^3 cubed. The base of the box is 25cm by 10cm.

How tall is the box of cereal?

Answer: 40cm

Step-by-step explanation:

Given the following :

Volume = 10,000cm^3

Base of box = 25cm by 10cm,

Base of box = Length × width

Therefore:

Length = 25cm, Width = 10cm

Volume = Lengh × Width × Height

10,000cm^3 = 25cm × 10cm × Height

10,000cm^3 = 250cm^2 × Height

Height = 10,000cm^3 ÷ 250cm^2

Height = 40cm

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A forest ranger is in a forest 2 miles from a straight road. A car is located c miles down the road. The forest ranger can walk

Tcecarenko [31]

Answer:

T(x) = (√(4+x^2))/2 +(c -x)/4
(a) x = 1.155 miles
(b) x = 1/2 mile

Step-by-step explanation:

The straight line distance from the starting point to the point x on the road is given by the Pythagorean theorem:

d1 = √(2²+x²)

The time required to walk that distance in the woods (at 2 miles per hour) is ...

time = distance / speed

t1 = √(4+x²)/2

The remaining distance along the road to the car is ...

d2 = c - x . . . . . for c > x

and the corresponding time at 4 mph is ...

t2 = (c -x)/4

Then the total time is ...

T(x) = t1 +t2

T(x) = √(4+x²)/2 +(c -x)/4

__

(a) The value of x that minimizes total time is the one that makes the derivative zero.

T'(x) = x/(2√(4+x²)) -1/4

0 = (2x -√(4+x²))/(4√(4+x²))

√(4+x²) = 2x . . . . . fraction is zero when numerator is zero; add radical

4 +x² = 4x² . . . . . . square both sides

4/3 = x² . . . . . . . . . subtract x², divide by 3

x = (2/3)√3 ≈ 1.1547

If c = 9 miles, x = 1.1547 miles.

__

(b) For c < (2/3)√3, the shortest travel time will be along the straight-line path to the car.

If c = 1/2 mile, x = 1/2 mile.

8 0

2 years ago

A rectangular area is formed having a perimeter of 40 cm. Determine the length and breadth of the rectangle if it is to enclose

Vilka [71]

Let x and y be the dimensions of the rectangle. If the perimeter is 40, we have

$2(x+y)=40 \iff x+y=20$

We can expression one variable in terms of the others as

$x+y=20 \iff x=20-y$

Since the area is the product of the dimensions, we have

$xy=(20-y)y=-y^2+20y$

This is a parabola facing down, so it's vertex is the maximum:

$f(y)=-y^2+20y \implies f'(y)=-2y+20$

So, the maximum is

$f'(y)=0 \iff -2y+20=0 \iff 2y=20 \iff y=10$

And since we know that $x+y=20$ , we have $x=10$ as well.

This is actually a well known theorem: out of all the rectangles with given perimeter, the one with the greatest area is the square.

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2 years ago

What is $0.8\%$ of $125\%$ of $8128$? Express your answer as a decimal.

anzhelika [568]

Answer:

The correct answer is $81.28

Step-by-step explanation:

In order to find this, we simply treat the word of as a multiplication symbol.

0.8% of 125% of $8128

Now change the percentages to decimals

0.008 * 1.25 * 8128 = 81.28

7 0

2 years ago

Gavin likes biking. He never misses a chance to go for a ride when the weather is nice. This week his goal is to bike about 65 t

andreyandreev [35.5K]

Answer:

How far should he ride on each of the four days to reach his goal?

1st day: $8$ miles

2nd day: $12$ miles

3rd day: $18$ miles

4th day: $27$ miles

Step-by-step explanation: As the problem says, $x$ is the number of miles he rides on the first day. Let's start off with that.

1st day: $x$ miles

He want to ride 1.5 times as far as he rode the day before... no 1.5 more, but 1.5 <em>times</em> as far as he rode the day before; you would multiply 1.5 with the previous day's length.

2nd day: $1.5x$

Then you multiply $1.5$ to $1.5x$ to get the third day's.

3rd day: $2.25x$

4th day: $3.375x$

----------------------------

Phew! Gavin wants to ride a total of 65 miles over these four days, so if Gavin added all the miles of the four days, he should get 65...

1st+2nd+3rd+4th=65

$x+1.5x+2.25x+3.375x=65$

$8.125x=65$

$\frac{8.125x}{8.125}=\frac{65}{8.125}$

$x=8$

Yes! Now that we've got the hard part done... substitute 8 for ever single $x$ .

1st day: $8$ miles

2nd day: $1.5(8)=12$ miles

3rd day: $2.25(8)=18$ miles

4th day: $3.375(8)=27$ miles

-------------------------

Checking my answer:

Just add the miles!

$8+12+18+27=65$

$65=65$

✓

-----------------------

Hope that helps! :D

5 0

2 years ago

Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Ghella [55]

Answer: The required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

Step-by-step explanation: Given that Mustafa, Heloise, and Gia have written more than a combined total of 22 articles for the school newspaper.

Also, Heloise has written $\frac{1}{4}$ as many articles as Mustafa has and Gia has written $\frac{3}{2}$ as many articles as Mustafa has.

We are to write an inequality to determine the number of articles, m, Mustafa could have written for the school newspaper. Also, to solve the inequality.

Since m denotes the number of articles that Mustafa could have written. Then, according to the given information, we have

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$

And the solution of the above inequality is as follows :

$x+\dfrac{1}{4}x+\dfrac{3}{2}x>22\\\\\\\Rightarrow \dfrac{4x+x+6x}{4}>22\\\\\\\Rightarrow 11x>88\\\\\Rightarrow x>\dfrac{88}{11}\\\\\Rightarrow x>8.$

Thus, the required inequality is $x+\dfrac{1}{4}x+\dfrac{3}{2}x>22.$ and its solution is $x>8.$

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2 years ago

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