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tiny-mole [99]
2 years ago
11

Suppose that the light from the pinhole projects onto a screen 3.00 meters away. What is the radius r1 of the first dark ring on

that screen? Notice that the angle from part a is small enough that sinθ≈tanθ.
Mathematics
1 answer:
Fittoniya [83]2 years ago
3 0

Answer:

16 mm

Step-by-step explanation:

The next information is misssing: The first dark ring can be found at angle 0.305 degrees.

A rigth triangle is formed in wich one leg is the radius r1 of the first dark ring and the other leg is the distance between the screen and the laser (L), which is equal to 3 meters.

Using the relationship sinθ≈tanθ we get:

tanθ = r1/L

tan 0.305  = r1 / 3

r1 =  tan(0.305°) * 3 m

r1 = 0.016 m = 16 mm

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The smallest number of tiles Quintin will need in order to tile  his floor is 20

The given parameters;

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To find:

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A_{floor} = 1000 \ cm \times 600 \ cm = 600,000 \ cm^2

The maximum number tiles needed (this will be possible if only one shape type is used)

maximum \ number= \frac{Area \ of \ floor}{total \ area \ of \ one \ shape \ type} \\\\maximum \ number= \frac{600,000 \ cm^2}{10,000 \ cm^2} \\\\maximum \ number=  60

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The minimum or smallest number of tiles needed (this will be possible if all the 3 different shapes are used)

3 \times \ smallest \ number  = 60\\\\smallest \ number = \frac{60}{3} \\\\smallest \ number = 20

Thus, the smallest number of tiles Quintin will need in order to tile  his floor is 20

Learn more here: brainly.com/question/13877427

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Step-by-step explanation:

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