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givi [52]
1 year ago
12

A farmer harvests apples that are heavier than the average 5 kg weight for that variety. He plants the seeds from the harvest ho

ping that the next generation will produce even heavier apples. Using the results found by Galton, which statement is most likely true regarding the weight of the next generation?
Mathematics
2 answers:
den301095 [7]1 year ago
5 0

The answer is (C)- The next generation will weigh less than the parent generation, closer to 5 kg.

Step-by-step explanation:

Ainat [17]1 year ago
5 0

Answer:

C: The next generation will weigh less than the parent generation, closer to 5 kg.

Edg. 2020.

Step-by-step explanation:

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lev has 9 tens. jim has 1 ten. they put all their tens together. dawn puts 9 ones with the tens. what number did they make?
MatroZZZ [7]
The answer to this 110

3 0
2 years ago
A theatre has the capacity to seat people across two levels, the Circle and
andriy [413]

Answer: 76.19\%

Step-by-step explanation:

<h3> The complete exercise is: " A theatre has the capacity to seat people across two levels, the Circle, and the stalls. The ratio of the number of seats in the circle to a number of seats in the stalls is 2:5. Last Friday, the audience occupied all the 528 seats in the circle and \frac{2}{3} of the seats in the stalls. What is the percentage of occupancy of the theatre last Friday?"</h3>

Let be "s" the total number of seats in the Stalls.

The problem says that the ratio of the number of seats in the Circle to the number of seats in the Stalls is 2:5.

Since the number of seats that were occupied last Friday was 528 seats, we can set up the following proportion:

\frac{2}{5}=\frac{528}{s}

Solving for "s", we get:

s*\frac{2}{5}=528\\\\s=528*\frac{5}{2}\\\\s=1,320

So the sum of the number of seats in the Circle and the number of seats in the Stalls, is:

Total=1,320\ seats+528\ seats=1,848\ seats

 We know that \frac{2}{3} of the seats in the Stalls were occupied. Then, the number of seat in the Stalls that were occupied is:

(1,320)(\frac{2}{3})=880

Therefore, the total number of seats that were occupied las Friday is:

Total\ occupied=880\ seats+528\ seats=1,408\ seats

Knowing this, we can set up the following proportion, where "p" is the the percentage of occupancy of the theatre last Friday:

\frac{100}{1,848}=\frac{p}{1,408}

Solving for "p", we get:

(1,408)(\frac{100}{1,848})=p\\\\p=76.19\%

8 0
1 year ago
Which statements are true about these lines? Select three<br> options.
gayaneshka [121]

i need the ancwer options and the linea

6 0
1 year ago
Stu hiked a trail at an average rate of 3 miles per hour. He ran back on the same trail at an average rate of 5 miles per hour.
fredd [130]
Let d =  the length of the trail, miles

Note that
distance = speed * time
or
time = distance / speed.

The time, t₁, to travel the trail at 3 miles per hour is
t₁ = d/3 hours
The time, t₂, to travel back at 5 miles per hour is
t₂ = d/5 hours

Because the total time is 3 hours, therefore
t₁ + t₂ = 3
d/3 + d/5 = 3
d(1/3 + 1/5) = 3
d(8/15) = 3
Multiply each side by 15.
8d = 3*15 =45
d = 45/8 = 5 5/8 miles or 5.625 miles
Total distance = 2*d = 11.25 miles or 11 1/4 miles.

t₁ = 5.625/3 = 1.875 hours or 1 hour, 52.5 minutes
t₂ = 5.625/5 = 1.125 hours or 1 hour , 7.5 minutes

Answers ;
Time to travel at 3 miles per hour = 1.875 hours (1 hour, 52.5 minutes)
Time to return at 5 miles per hour = 1.125 hours (1 hour, 7.5 minutes)
Total distance traveled = 2*d = 11.25 miles.

6 0
2 years ago
Read 2 more answers
Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m\overarc RS + m\overarc ST + m\overarc TQ + m\overarc
LekaFEV [45]

Answer:

360°

Step-by-step explanation:

From the figure attached,

R, S, T and Q are the points on a circle O.

Since, "measure of an arc of a circle is equal to the measure of the angle subtended by the arc at the center."

By this statement,

m(\widehat{RS})=m(\angle ROS)

m(\widehat{ST})=m(\angle SOT)

m(\widehat{TQ})=m(\angle TOQ)

m(major arc RQ) = m(∠QOR)

Now m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major arc RQ) = m(\angle ROS)+m(\angle SOT)+m(\angle TOQ)+m(\angle QOR)

Since sum of all angles at a point = 360°

m(\widehat {RS})+m(\widehat{ST})+m(\widehat{TQ}) + m(major arc RQ) = 360°

4 0
1 year ago
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