All categories

2 years ago

Write a quadratic function f whose only zero is -9

Mathematics

2 answers:

frutty [35]2 years ago

7 0

Answer:

x² + 18x + 81 = 0

Step-by-step explanation:

For the zero to -9, the equation has to be x + 9.

x = -9

x + 9 = 0

Since the only zero is -9, square the equation. Expand to get the function

(x + 9)² = 0

x² + 18x + 81 = 0

Radda [10]2 years ago

7 0

Answer:

$x^{2}+18x+81=0$

Step-by-step explanation:

For it to have zero of -9 it is (x+9)^2. Expand that out and you get the answer.

You might be interested in

Kira keeps track of how much time she spends walking her dog each morning. Her data

NemiM [27]

Answer:18 minutes

Step-by-step explanation:

You have to subtract the numbers from the end from each other and u get the range wh i.c h is18

8 0

2 years ago

Read 2 more answers

The table shows ordered pairs of the function y = 16 + 0.5x . Which ordered pair could be the missing values represented by (x,

lawyer [7]

The correct answer is:

(8, 20).

Explanation:

We can substitute the values for x in the equation and see if they equal y:

y=16+0.5(0) = 16+0 = 16 ≠ 18. This is not the correct option.

y=16+0.5(5) = 16+2.5 = 18.5 ≠ 19.5. This is not the correct option.

y=16+0.5(8) = 16+4 = 20. This is the correct option.

3 0

2 years ago

Read 2 more answers

H(y) models the leading number of home runs for season y on the National League between the years 2000-2010, according to the ta

alexandr1967 [171]

Answer:

Integers

2000 $\leq$ x $\leq$ 2010

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which products result in a difference of squares? Select three options. A. (x minus y)(y minus x) B. (6 minus y)(6 minus y) C. (

solniwko [45]

Answer:

Step-by-step explanation:

Hello, please consider the following.

A. (x minus y)(y minus x)

$(x-y)(y-x)=-(x-y)(x-y)=-(x-y)^2$

This is not a difference of squares.

B. (6 minus y)(6 minus y)

$(6-y)(6-y)=(6-y)^2$

This is not a difference of squares.

C. (3 + x z)(negative 3 + x z)

This is a difference of squares.

$\boxed{(3+xz)(-3+xz)=(xz+3)(xz-3)=(xz)^2-3^2}$

D. (y squared minus x y)(y squared + x y)

This is a difference of squares.

$\boxed{(y^2-xy)(y^2+xy)=(y^2)^2-(xy)^2}$

E. (64 y squared + x squared)(negative x squared + 64 y squared)

This is a difference of squares.

$\boxed{(64y^2+x^2)(-x^2+64y^2)=(64y^2+x^2)(64y^2-x^2)=(64y^2)^2-(x^2)^2}$

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

6 0

1 year ago

Read 2 more answers

2-8 Examine the function h(x) defined at right. Then estimate the values Below.

Arada [10]

We are given graph of the function.

Let us do given parts one by one.

a) h(1).

Here, we need to find the value of function (y-coordinate) for x=1.

From the given graph, we can see the for x=1 value of y is 2.

Therefore, h(1)=2.

b) h(3).

Here, we need to find the value of function (y-coordinate) for x=3.

From the given graph, we can see the for x=3 value of y is -4.

Therefore, h(3)=-4.

c) x when h(x) =0.

Here, we need to find the value of x-coordinate for y=0.

From the given graph, we can see the for y=0 value of x is also 0.

Therefore, x=0 when h(x)=0.

d) h(-1).

Here, we need to find the value of function (y-coordinate) for x=-1.

From the given graph, we can see the for x=-1 value of y is -2.

Therefore, h(-1)=-2.

e) h(-4).

Here, we need to find the value of function (y-coordinate) for x=-4.

From the given graph, we can see the for x=-4 value of y is 13.

Therefore, h(-4)=13.

5 0

1 year ago