Question

Bruce's speed when swimming in still water is 5 meters/second. He is swimming in a direction 25° east of north. The current is moving 3.5 meters/second at an angle of 60° west of south. Identify Bruce's vector, the current's vector, and the vector representing Bruce's actual motion.

Answer 1

Answer:

<2.1130913087, 4.53153893518>;  <−3.03108891325, −1.75>; <−0.91799760455, 2.78153893518>

Step-by-step explanation:

Bruce's vector is <5cos(90-25), 5sin(90-25)> = <5cos(65), 5sin(65)> ≈ <2.1130913087, 4.53153893518>

The wind's vector is <3.5cos(270-60), 3.5sin(270-60)> = <3.5cos(210), 3.5sin(210)>  ≈ <−3.03108891325, −1.75>

You add them together to find his actual motion:

<−0.91799760455, 2.78153893518>