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jeka57 [31]
1 year ago
8

5. Anthony has 80 pine tree seedlings to plant in his meadow. He first plants one row of 12

Mathematics
1 answer:
inna [77]1 year ago
7 0
D. 16 clusters
Hope it helps
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Olivia wants to cut 3 3/4 inches from a piece of string.She has already cut off 2 9/16 inches from the piece of string.How much
Roman55 [17]

Answer: she still has to cut off 19/16 inches.

Step-by-step explanation:

Olivia wants to cut 3 3/4 inches from a piece of string. Converting 3 3/4 inches to improper fraction, it becomes 15/4 inches.

She has already cut off 2 9/16 inches from the piece of string. Converting 2 9/16 inches to improper fraction, it becomes 41/16 inches.

Therefore, the length of string that is left for her to cut off would be

15/4 - 41/16 = (60 - 41)/16

= 19/16 inches

6 0
2 years ago
You own a house and land with an assessed value of $55,580. Every year, you pay a total of $2,834.58 in property taxes. What is
Ludmilka [50]
Tax rate = property taxes / assessed value 
= 2,834.58 / 55,580
= 0.051

the answer is A.

4 0
2 years ago
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Which graph represents the solution set of the compound inequality?<br><br> −5 &lt; a − 4 &lt; 2
never [62]

-5 < a - 4 < 2\\\\ -1

the 3rd one

8 0
1 year ago
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Juan told Sylvia he got a $0.50 raise this week and his new hourly rate will be $10.25 an hour. Sylvia wants to know what Juan’s
zhenek [66]

Answer:

The correct answer is:

r + 0.50 = 10.25: Subtract .50 from both sides. The answer is $9.75.

This is because Juan got a $0.50 raise which means that his new rate will be $0.50 more than his original rate (r).

6 0
1 year ago
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The measures in the table describe the weights of animals that visited a vet on one day, in pounds. Mean Median Mode Mean Absolu
MrMuchimi

Answer: On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.

If the MAD of weights for another day was 1.5, then that day's weights would be less variable than the weights of pets seen on this day.

Step-by-step explanation:

Given: The measures in the table describe the weights of animals that visited a vet on one day, in pounds.

Mean = 12.9

Median= 12.0

Mode = 12.0

Mean Absolute Deviation = 2.4

We know that the mean absolute deviation (MAD) of a data set is the mean distance between each and every data value and the mean.It tells about the variation in a data set.

Therefore, On average, the weight of a pet visiting this vet on this day is about 2.4 pounds away from 12.9 pounds.

Also, If the MAD of weights for another day was 1.5, and since 1.5< 2.4.

Then that day's weights would be less variable than the weights of pets seen on this day.

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1 year ago
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