Given functin is :
![f\left(x\right)=\sqrt[5]{x}](https://tex.z-dn.net/?f=f%5Cleft%28x%5Cright%29%3D%5Csqrt%5B5%5D%7Bx%7D)
We know that the domain of the expression is all real numbers except where the expression is undefined. In given function, there is no real number that makes the expression undefined. Hence domain is all real numbers.
Domain: (-∞,∞)
Range is the set of y-values obtained by plugging values from domain so the range will also same.
Range: (-∞,∞)
If we increase value of x then y-value will also increase so that means it is an INCREASING function. You can also verify that from graph.
It crosses x and y-axes both at the origin
Hence x-intercept=0 and y-intercept=0
Graph is not symmetric about y-axis hence it can't be EVEN
Graph is not symmetric about origin so it is ODD.
There is no breaking point in the graph so that means it is a Continuous function.
There is no hoirzontal or vertical or slant line which seems to be appearing to touch the graph at infinity so there is NO asymptote.
END behaviour means how y-changes when x approaches infinity.
From graph we can see that when x-approaches -∞ then y also approaches ∞.
when x-approaches +∞ then y also approaches +∞.
Answer:
5.75x10^11
Step-by-step explanation:
quotient of 2,300 and (0.4x10^-8) is
2,300 ÷ (0.4x10^-8)
2300 = 2.3x10^3
We now have
2.3x10^3 / 0.4x10^-8
= (2.3/0.4) x ( 10^(3 - (-8))
= 5.75 x (10^(3+8))
= 5.75 x (10^11)
= 5.75x10^11
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Û = (-1, -1, -1)
^v = (2, 3, -5)
^v - û = (2 + 1, 3 + 1, -5 + 1) = (3, 4, -4)
Half way from ^v to ^(v - u) = ((3 - 2)/2, (4 - 3)/2, (-4 + 5)/2) = (1/2, 1/2, 1/2)
Halfway from û to ^v = ((2 + 1)/2, (3 + 1)/2, (-5 + 1)/2) = (3/2, 2, -2)
The required vector ^w = ((3/2 - 1/2), (2 - 1/2), (-2 - 1/2)) = (1, 1/2, -5/2)
Just take the coordinates of both those red dots and use the slope formula: y2-y1 all divided by x2-x1. that should give you slope
Answer:
= 391/11
Let say number = N
a certain number is increased by 5
= N + 5
,one-half of the result
= (N + 5)/2
Three -fifths of the excess of 61 over the number.
= (3/5)(61 - N)
Equating both
(N + 5)/2 = (3/5)(61 - N)
multiplying by 10 both sides
=> 5(N + 5) = 6(61 - N)
=> 5N + 25 = 366 - 6N
=> 11N = 391
=> N = 391/11
Step-by-step explanation: