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MrMuchimi
2 years ago
11

Hadi earned $120.00 from his job yesterday. Today he expects to earn 15% less than yesterday and tomorrow he expects to earn 15%

more than today. What is the combined amount Hadi expects to earn for three days
Mathematics
2 answers:
andreev551 [17]2 years ago
7 0
Yesterday Hadi earned: $120

Today he will earn: $120*85% = $102
(You times the amount yesterday by 85% because you want to find the 15% less of 100% of the amount he's earned yesterday. Therefore, to find 15% less than yesterday you multiply it by 85% (100% - 15%) )

Tomorrow he will earn: $102*115% = $117.30
(Same thing here, however you are finding 15% more than 100% today. Therefore, you multiply the amount he earned today it by 115% (100% + 15%) )

To find the amount he earns for the three days you must add the amount earned of yesterday, today and tomorrow earned from the working above.

<span>Therefore, Hadi expects to earn: </span>
<span>Yesterday + Today + Tomorrow = 120 + 102 + 117.30 = $339.3</span>
alexira [117]2 years ago
3 0
Yesterday Hadi earned: $120

Today he will earn: $120*85% = $102
(You times the amount yesterday by 85% because you want to find the 15% less of 100% of the amount he's earned yesterday. Therefore, to find 15% less than yesterday you multiply it by 85% (100% - 15%) )

Tomorrow he will earn: $102*115% = $117.30
(Same thing here, however you are finding 15% more than 100% today. Therefore, you multiply the amount he earned today it by 115% (100% + 15%) )

To find the amount he earns for the three days you must add the amount earned of yesterday, today and tomorrow earned from the working above.

Therefore, Hadi expects to earn:
Yesterday + Today + Tomorrow = 120 + 102 + 117.30 = $339.3


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In a trapezoid the lengths of bases are 11 and 18. The lengths of legs are 3 and 7. The extensions of the legs meet at some poin
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Answer: The length of segments between this point and the vertices of greater base are 7\frac{5}{7} and 18.

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Let P is the point where The extended legs meet,

So, according to the question, we have to find out : AP and BP

In Δ APB and Δ DPC,

∠ DPC ≅ ∠APB ( reflexive)

∠ PDC ≅ ∠ PAB    ( By alternative interior angle theorem)

And, ∠ PCD ≅ ∠ PBA  ( By alternative interior angle theorem)

Therefore, By AAA similarity postulate,

\triangle APB\sim \triangle D PC

Let, DP =x

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⇒ x = 33/7= 4\frac{5}{7}

Thus, PD= 4\frac{5}{7}

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⇒ y = 77/7 = 11

Thus, PC= 11

But, PB= PC + CB

PB= 11+7 = 18



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