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Svetradugi [14.3K]
2 years ago
6

Lorena calculated the slope of the linear function that is represented by the table of values as shown. x y –10 15 –8 27 –6 39 –

4 51 –2 63 m = StartFraction y 2 minus y 1 Over x 2 minus x 1 EndFraction = StartFraction 63 minus 51 Over negative 2 minus (negative 4) EndFraction = StartFraction 12 Over negative 6 EndFraction = negative 2. What did she do wrong? She used the wrong formula for slope. She used the wrong points to determine the slope. She made a mistake when she subtracted x 1 from x 2. She made a mistake when she subtracted y 1 from y 2.
Mathematics
2 answers:
Anvisha [2.4K]2 years ago
4 0

She made a mistake when she subtracted x1 from x2.

Step-by-step explanation:

Step 1 :

a)

The formula used by Lorena to calculate the slope between 2 points is correct

So the statement given in option 1 is not the reason for her mistake

Step 2:

b)

She has taken the fourth and fifth point and correctly used the x and y co ordinates to calculate the slope

Hence the statement in second option is not true

Step 3:

c)

While calculating the slope the denominator is -2 - (-4) . This gives 2 as the answer. But she has made a mistake in this subtraction giving -6 as the answer.

Hence she has made a mistake in subtracting x1 from x2 and this statement is true

Step 4:

d)

She has not made any mistake in subtracting y1 from y2. Hence this statement is not true

Nataly [62]2 years ago
4 0

Answer:

she made a mistake when she subtracted y1 from y2

Step-by-step explanation:

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The features in a function can be used to describe real-world events. The features and their match are:

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  • <em>range: all possible areas of the bell pepper patch</em>

<em />

For Melissa's garden, the input and output variables are:

  • <em>Input: tomato patch</em>
  • <em>Output: bell pepper patch</em>

The range is the list of possible output values, while the domain is the list of possible input values.

This means that: the range is all possible areas of the bell pepper patch while the domain is all possible lengths of the tomato patch

Also, the x and y intercepts are when the values of the output and input variables are 0, respectively.

Using the above comparison;

The y - intercept is the area of the bell pepper patch when the length of the tomato patch is 0, while the x - intercept is the length of the tomato patch when the area of the bell pepper patch is 0.

Read more about functions at:

brainly.com/question/14180189

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The slope of the line below is -2. Use the coordinates of the labeled point to find the point-slope equation of the line. 
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Given: KL ║ NM , LM = 45, m∠M = 50° KN ⊥ NM , NL ⊥ LM Find: KN and KL
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Answer:

KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08\\ \\KN=45\sin 50^{\circ}\approx 34.47

Step-by-step explanation:

Given:

KL ║ NM ,

LM = 45

m∠M = 50°

KN ⊥ NM  

NL ⊥ LM

Find: KN and KL

1. Consider triangle NLM. This is a right triangle, because NL ⊥ LM. In this triangle,

LM = 45

m∠M = 50°

So,

\tan \angle M=\dfrac{\text{opposite leg}}{\text{adjacent leg}}=\dfrac{NL}{LM}=\dfrac{NL}{45}\\ \\NL=45\tan 50^{\circ}

Also

m\angle LNM=90^{\circ}-50^{\circ}=40^{\circ} (angles LNM and M are complementary).

2. Consider triangle NKL. This is a right triangle, because KN ⊥ NM . In this triangle,

NL=45\tan 50^{\circ}

m\angle KLN=m\angle LNM=40^{\circ} (alternate interior angles)

m\angle KNL=90^{\circ}-40^{\circ}=50^{\circ} (angles KNL and KLN are complementary).

So,

\sin \angle KNL=\dfrac{\text{opposite leg}}{\text{hypotenuse}}=\dfrac{KL}{LN}=\dfrac{KL}{45\tan 50^{\circ}}\\ \\KL=45\tan 50^{\circ}\sin 50^{\circ}\approx 41.08

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\cos \angle KNL=\dfrac{\text{adjacent leg}}{\text{hypotenuse}}=\dfrac{KN}{LN}=\dfrac{KN}{45\tan 50^{\circ}}\\ \\KN=45\tan 50^{\circ}\cos 50^{\circ}=45\sin 50^{\circ}\approx 34.47

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Answer:

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or

10+10=20

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