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AnnZ [28]
2 years ago
6

7is subtracted from the quotient of 48 divided by the sum of 5 & difference of 11 and 8​

Mathematics
2 answers:
kramer2 years ago
5 0

Answer:

7-48=41

÷

5+11-8

bodmas

5+3=8

41÷8=5.125

Vlad1618 [11]2 years ago
4 0

Answer:

-1

Step-by-step explanation:

48/(5+(11-8) -7

48/(5+3) -7

48/8 -7

6-7

-1

i hope it helped you. i tried you help you

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What is the discriminant of the quadratic equation 0 = 2x2 + 3x - 5?
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Answer:

0=4+3x-5 calculate

0=-1×3x move variable to the left

-3x=-1 divide both sides by -3

x=1 over 3

5 0
2 years ago
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Marissa ate six slices of pizza from the 16-piece large pizza. What percent of the pizza did she eat?
olya-2409 [2.1K]

Answer:

0.96%

Step-by-step explanation:

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7 0
2 years ago
During winter months freshwater fish sense the water getting colder,finding lakes and rivers to find warmer water.If a fish swim
atroni [7]
I believe this would be 28 feet. You find this by dividing 7/8 to get the decimal of the fraction. (Which is 0.875) Then multiply by 32 ft to get the answer. Hope this helps!
7 0
2 years ago
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Ramona's backyard is fenced and represented by parallelogram YARD with measures in meters. She installed a 12-meters fence to se
Alisiya [41]
The fencing line x is the height of a rectangle triangle of base = y, hypothenuse of 9 m, so we use Pythagoras theorem to solve:

hyp^2 = height^2 + base^2
9^2 = x^2 + y^2
x^2 = 81 - y^2


we can see that x is also the height of another rectangle triangle of base = 15 - y, hypothenuse of 12 m, so we use Pythagoras theorem to solve:
hyp^2 = height^2 + base^2
12^2 = x^2 + (15 - y)^2

lets expand:
144 = x^2 + 225 - 30y + y^2

substitute x^2 from the first equation in the last:
144 = 81 - y^2 + 225 - 30y + y^2
144 = 81 + 225 - 30y
30y = -144 + 81 + 225
y = 5.4 m

substitute in the fence equation:
x^2 = 81 - y^2
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3 0
2 years ago
1. Dennis made a 500 km trip in five hours. For the first two hours, Dennis had an average speed of 150 km/h. For the last two h
Sati [7]

Answer:

The correct option is;

Dennis must have stopped for an hour in the middle of this trip

Step-by-step explanation:

The given parameters are;

The distance Dennis covered in 5 hours = 500 km

Dennis's average speed in the first two hours = 150 km/h

Dennis's average speed in the last two hours = 100 km/h

Therefore;

Dennis traveled 150 km/h × 2 h = 300 km in the first two hours

Dennis traveled 100 km/h × 2 h = 200 km in the last two hours

Which gives, Dennis traveled 300 km + 200 km in  2h + 2h = 4h

Therefore, Dennis traveled 500 km in 4 hours and Dennis must have stopped for an hour in the middle of this trip.

6 0
1 year ago
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