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Georgia [21]
2 years ago
11

Seth walks 1 1/4 miles in 5/12 hour. what is seth's unit rate?

Mathematics
2 answers:
Semmy [17]2 years ago
6 0
2 1/12 you do 1 1/4 divided by 5/12 which gives you 2 1/12. Also unit rate is asking the first rate.....
denpristay [2]2 years ago
4 0

Answer: 3 miles per hour.


Step-by-step explanation:

Given: Distance traveled by Seth = 1\frac{1}{4}\ miles

Convert into improper fraction, we get

Distance traveled by Seth = \frac{5}{4}\ miles

Time taken by Seth to travel the given distance = \frac{5}{12}\ hour

The unit rate of Seth = \frac{distance}{time}=\frac{\frac{5}{4}}{\frac{5}{12}}=\frac{12}{4}=3\ miles\ per\ hour

Hence, the unit rate of Seth = 3 miles per hour


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Jan accidentally ran 7 minutes longer than she was supposed to. Write an expression for the total amount of time Jan ran if she
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Answer:

m+7

Step-by-step explanation:

If she ran 7 minutes longer and m represents the amount of time she ran, then it would just be addition.

Let's say m=60 minutes. She would've ran for 67 minutes, which is also m+7.

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2 years ago
Find the slope of line
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The profit earned by a sporting goods outlet is modeled in the graph below, where x is the number of years since the outlet open
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The domain would be x ≥ 0.

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2 years ago
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If George is 33 1/3% richer than Pete, than Pete is what percent poorer than George?
OleMash [197]

Answer:

25%

Step-by-step explanation:

George is 33\frac{1}{3}% (\frac{100}{3}%) richer than Pete. Let Pete's percentage of wealth be 100%.

Thus George percentage of wealth = 100% + \frac{100}{3}%

                                                           = \frac{400}{3}%

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Pete's percent poorer than George can be determined by;

                                                           = (\frac{100}{3}) ÷ (\frac{400}{3} ) × 100

                                                           = (\frac{100}{3}) × \frac{3}{400} ×100

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Pete is 25% poorer than George.

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2 years ago
Willis analyzed the following table to determine if the function it represents is linear or non-linear. First he found the diffe
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