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ANEK [815]
2 years ago
12

Shane and Abha earned a team badge that required their team to collect no less than 20002000 cans for recycling. Abha collected

178178 more cans than Shane did.
Write an inequality to determine the number of cans, SS, that Shane could have collected.

What is the solution set of the inequality?
Mathematics
1 answer:
yKpoI14uk [10]2 years ago
3 0

Shane and Abha earned a team badge that required their team to collect no less than 2000 cans for recycling.

This means a minimum of 2000 cans are needed.

Abha collected 178 more cans than Shane did.

Let us suppose that the cans collected by Shane = S

So, Abha collected = S+178

The inequality to determine the cans Shane collected can be given by :

S+S+178\geq 2000

= 2S+178\geq 2000

2S\geq 2000-178

2S\geq 1822

S\geq 911

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Any fraction in which the numerator's value is the same as the denominator's value will equal 1. For example:

7/7, 6/6, 500/500, etc.

<em>~Rise Above the Ordinary</em>

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12. Venu and Tanuj are running along a circular track. They take 48 seconds and 56 seconds to
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Answer:

The meet at first time at starting point after 336 seconds,

Vanu have completed 7 laps while Tanuj has completed 6 laps.

Step-by-step explanation:

Given that Venu and Tanuj take 48 seconds and 56 seconds to

complete a lap respectively.

To meet them again at the startiong point, the  time taken must be multiple of 56 and 48.

So, the minimum time required to meet them again at the startiong point is time taken for first time meet.

Time taken to first time meet is the smallest number which can be divided by 56 and 48, i.e the lowest common factor (LCM) of 56 and 48 which is 336 seconds or 5 minutes 36 seconds.

Number of laps by Venu

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2 years ago
Which graph represents the equation x2 = 8y?
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2 years ago
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Two production lines are used to pack sugar into 5 kg bags. Line 1 produces twice as many bags as does line 2. One percent of ba
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Answer:

P(Bag is Defective) = 0.0167

Step-by-step explanation:

Line 1 produces twice as many bags as line 2. Let x be the number of bags produced by line 2.

No. of bags produced by line 2 = x

No. of bags produced by line 1 = 2x

Probability that the bag has been produced by line 1 can be written as:

P(Line 1) = No. of bags produced by line 1/Total no. of bags

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P(Line 1) = 2/3. Similarly,

P(Line 2) = x/3x

P(Line 2) = 1/3

1% bags produced by line 1 are defective so the probability of line 1 producing a defective bag is:

P(Defective|Line 1) = 0.01

3% of bags from line 2 are defective, so:

P(Defective|Line 2) = 0.03

b. The probability that the chosen bag is defective can be calculated through the conditional probability formula:

P(A|B) = P(A∩B)/P(B)

<u>P(A∩B) = P(A|B)*P(B)</u>

The chosen defective bag can be either from line 1 or from line 2. So, the probability that the chosen bag is defective is:

P(Bag is Defective) = P(Defective and from Line 1) + P(Defective and from Line 2)

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                                = P(Defective|Line 1)*P(Line 1) + P(Defective|Line 2)*P(Line 2)

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STEP 2:
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STEP 4: 
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Answer: Minimum Sample Size is 1691
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