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RideAnS [48]
1 year ago
10

In a return-standard deviation space, which of the following statements is(are) true for risk-averse investors? (The vertical an

d horizontal lines are referred to as the expected return-axis and the standard deviation-axis, respectively.) I) An investor's own indifference curves might intersect. II) Indifference curves have negative slopes. III) In a set of indifference curves, the highest offers the greatest utility. IV) Indifference curves of two investors might intersect.
Mathematics
1 answer:
Wewaii [24]1 year ago
5 0

Answer:

Option iii) and iv) are the correct option

Step-by-step explanation:

Correct option is  - III and IV only

I) investors indifference curves are parallel they canno be intersect (False)

II) Indifference curve always be in a positive slope hence the statement is (False)

III) In a set of indifference curves, the higher the risk , the higher the return and as such the highest offers the greatest utility. (True)

IV) Indifference curve of investors with a same risk return trade off might intersect . (True)

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Max's cell phone plan charges a monthly
ludmilkaskok [199]

Answer:

21

Step-by-step explanation:

7.41 / 0.13 = 57

57 - 15 = 42

42 / 2 = 21

21, 36

6 0
1 year ago
Which is greater 3.6 m or 36 cm?
WARRIOR [948]

Answer:

36

Step-by-step explanation:

36 is greater than 3.6

7 0
2 years ago
Read 2 more answers
Of 1,050 randomly selected adults, 360 identified themselves as manual laborers, 280 identified themselves as non-manual wage ea
garik1379 [7]

Answer:

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

Step-by-step explanation:

We have a sample of executives, of size n=160, and the proportion that prefer trucks is 26%.

We have to calculate a 95% confidence interval for the proportion.

The sample proportion is p=0.26.

 

The standard error of the proportion is:

\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.26*0.74}{160}}\\\\\\ \sigma_p=\sqrt{0.0012}=0.0347

The critical z-value for a 95% confidence interval is z=1.96.

The margin of error (MOE) can be calculated as:

MOE=z\cdot \sigma_p=1.96 \cdot 0.0347=0.068

Then, the lower and upper bounds of the confidence interval are:

LL=p-z \cdot \sigma_p = 0.26-0.068=0.192\\\\UL=p+z \cdot \sigma_p = 0.26+0.068=0.328

The 95% confidence interval for the population proportion is (0.192, 0.328).

We can claim with 95% confidence that the proportion of executives that prefer trucks is between 19.2% and 32.8%.

3 0
2 years ago
AT&T has a family plan of four lines for $125 and additional lines are $15 each per month. If Jason wants to spend at most $
denis-greek [22]

Given:

Cost of four lines = $125

Cost of each additional line = $15

Jason wants to spend at most $200 per month on cell phone expenses.

To find:

The inequality for the given situation.

Solution:

Let x be the number of additional line.

Cost of one additional line = $15

Cost of x additional line = \$15x

Total cost = Fixed cost + Addition cost

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It is given that Jason wants to spend at most $200 per month on cell phone expenses. It means the total cost must be less than or equal to 200.

125+15x\leq 200

Therefore, the correct option is C.

8 0
2 years ago
What is the solution to this system of equations? Y= 2x - 3.5 x - 2y = -14
goldfiish [28.3K]

Answer:

x=7

y=10.5


Step-by-step explanation:

1. You can apply the method of substitution, as you can see below:

- Substitute y=2x-3.5 into the other equation and solve fo x:

x-2(2x-3.5)=-14\\x-4x+7=-14\\x=7

- Substitute the value of x obtain into the first equation, then the value of y is:

y=2(7)-3.5\\y=10.5


6 0
1 year ago
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