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RideAnS [48]
2 years ago
10

In a return-standard deviation space, which of the following statements is(are) true for risk-averse investors? (The vertical an

d horizontal lines are referred to as the expected return-axis and the standard deviation-axis, respectively.) I) An investor's own indifference curves might intersect. II) Indifference curves have negative slopes. III) In a set of indifference curves, the highest offers the greatest utility. IV) Indifference curves of two investors might intersect.
Mathematics
1 answer:
Wewaii [24]2 years ago
5 0

Answer:

Option iii) and iv) are the correct option

Step-by-step explanation:

Correct option is  - III and IV only

I) investors indifference curves are parallel they canno be intersect (False)

II) Indifference curve always be in a positive slope hence the statement is (False)

III) In a set of indifference curves, the higher the risk , the higher the return and as such the highest offers the greatest utility. (True)

IV) Indifference curve of investors with a same risk return trade off might intersect . (True)

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Which is equivalent to-2(4-3x)+ (5x-2)
almond37 [142]

Answer:

Step-by-step explanation:

-2(4-3x)+(5x-2)

-8+6x+5x-2

11x-10

3 0
2 years ago
Consider the initial value problem y′+4y=48t,y(0)=9. y′+4y=48t,y(0)=9. Take the Laplace transform of both sides of the given dif
Nadusha1986 [10]

Answer:

sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

Step-by-step explanation:

given is the Differential equation in I order linear as

y′+4y=48t,y(0)=9.

Take Laplace on both sides

L(y') +4L(y) = 48L(t)\\sY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2} \\Y(s) [s+4]=\frac{48}{s^2}+9\\Y(s) = \frac{1}{s^2(s+4)}+\frac{9}{s+4}

Now if we take inverse we get y(t) the solution

Thus the algebraic equation would besY(s)-y(0) +4Y(s) = 48 *\frac{1}{s^2}

8 0
1 year ago
Identify the triangle that contains an acute angle for which the sine and cosine ratios are equal. 1. Triangle A B C has angle m
MAXImum [283]

Answer:

The correct option: (2) Triangle ABC that has angle measures 45°, 45° and 90°.

Step-by-step explanation:

It is provided that a triangle ABC has an acute angle for which the sine and cosine ratios are equal to 1.

Let the acute angle be m∠A.

For the sine and cosine ratio of m∠A to be equal to 1, the value of Sine of m∠A should be same as value of Cosine of m∠A.

The above predicament is possible for only one acute angle, i.e. 45°, since the value of Sin 45° and Cos 45° is,  

                                 Sin\ 45^{o} =Cos\ 45^{o} = \frac{1}{\sqrt{2} }

So for acute angle 45° the ratio of Sin 45° and Cos 45° is:

                                         \frac{Sin\ 45^{o}}{Cos\ 45^{o}} = \frac{\frac{1}{\sqrt{2} } }{\frac{1}{\sqrt{2} } } = 1

Hence one of the angles of a triangle is, m∠A = 45°.

Comparing with the options provided the triangle is,

Triangle ABC that has angle measures 45°, 45° and 90°.

Thus, the provided triangle is a right angled isosceles triangle, since it has two similar angles.

7 0
2 years ago
Karina put a $300 pair of earrings on layaway by making a 10% down
abruzzese [7]

Answer:

8 weeks is the right APEX ANSWER

7 0
2 years ago
P=100a÷t solve for a
pishuonlain [190]

<u><em>a=1/100pt is the correct answer.</em></u> First you had to multiply by t from both sides of equation, and it gave us, ⇒ pt=100a. And then you had to flip an equation, and it gave us, ⇒100a=pt. You can also divide by one-hundred (100) from both sides of equation, and it gave us, \frac{100a}{100}=\frac{pt}{100}. And finally, and it gave us the answer is a=1/100pt is the final answer. Hope this helps! And thank you for posting your question at here on brainly, and have a great day. -Charlie

8 0
2 years ago
Read 2 more answers
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