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alexdok [17]
2 years ago
8

Question 5 Six pairs of shoes cost as much as 1 coat, 2 pairs of jeans cost as much as 3 pairs of shoes, and 4 pairs of socks co

st as much as one pair of jeans. How many coats could I exchange for 64 pairs of socks?
A : 4 B: 1 C: 2 D: 3 E: None of these
Mathematics
1 answer:
Svetlanka [38]2 years ago
8 0
4 socks  = 1 pair of jeans
2 jeans = 3 shoes
6 shoes = 1 coat

1 pair of jeans = 4 socks...so 2 jeans = 8 socks
so now we have 8 socks = 3 shoes.
if 3 shoes = 8 socks, then 6 shoes = 16 socks
so 16 socks = 1 coat
so 64 socks = 64/16 = 4 coats <===
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Adam must fly home to city A from a business meeting in city B. One flight option flies directly to city A from​ B, a distance o
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The value  is  k =109.6 \ miles

Step-by-step explanation:

The diagram illustrating the question is shown on the first uploaded image

From the question we are told that

   The distance from city A to B is   AB =  467.3 miles

   The bearing from B to  C is  \theta_{BC} =  N 28.7E

   The bearing from B to  A is  \theta_{BA} =  N 60.7E

   The  bearing from A to  B is   \theta_{AB} =  S60.7W

    The  bearing from A to  C is   \theta_{AC} =  S79.1W

Generally from the diagram

     \theta_A  =  180 - 60.7 -79.1

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Also

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and  

      \theta_C  =  180 - (\theta_A  +\theta_B )

=>   \theta_C  =  180 - (40.2  + 32 )

=>   \theta_C  =  107.8 ^o

Generally according to Sine Rule

     \frac{BC}{sin (\theta_A)}  = \frac{CA}{sin (\theta_B)} =\frac{AB}{sin (\theta_C)}

=>   \frac{BC}{sin (40.2)}  = \frac{CA}{sin (32)} =\frac{467.3 }{sin (107.8)}    

So

     \frac{BC}{sin (40.2)}  = \frac{467.3 }{sin (107.8)}

=>  BC = 316.8 \ miles

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    CA = 260 .1 \ miles

Generally the additional flyer miles that Adam will receive if he takes the connecting flight rather than the direct​ flight is mathematically represented as

      k = [CA +BC]  - AB

=>     k = [260 .1 +316.8]- 467.3

=>  k =109.6 \ miles

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