Answer:
How many standard deviations above the mean is 14,500 hours? 1.25 1.5 2.5 Using the standard normal table, the probability that Seth's light bulb will last no more than 14,500 (P(z ≤ 1.25)) hours is about ✔ 89% .
Answer:
The answer to your question is below
Step-by-step explanation:
1.
2p + 2 ⇒ Quotient
Divisor ⇒ 2p - 2 4p² + 0p + 6 ⇒ Divident
-4p² + 4p
0 + 4p + 6
- 4p + 4
0 + 10 ⇒ Remainder
2. The dividend is 4p2 + 0p + 6.
The quotient is 2p + 2 + .
The remainder over the divisor is 10 / (2p - 2) .
To check the answer, multiply 2p + 2 + times 4p2 + 0p + 6 and verify that it equals the divisor.
(2p - 2)(2p + 2) = 4p⁴ + 4p - 4p - 4
= 4p⁴ - 4 + 10
= 4p⁴ + 10
<span>Most ancient societies had symbols to represent numbers, but they did not have symbols to represent operations or unknown quantities. Thus, the problems and solutions to the problems had to be written in word form.</span>
Is there any answer choices? I need the expressions to see which is equivalent to <span>(n + 12) x 5+7n</span>
Answer:
a) 
b) Wind capacity will pass 600 gigawatts during the year 2018
Step-by-step explanation:
The world wind energy generating capacity can be modeled by the following function

In which W(t) is the wind energy generating capacity in t years after 2014, W(0) is the capacity in 2014 and r is the growth rate, as a decimal.
371 gigawatts by the end of 2014 and has been increasing at a continuous rate of approximately 16.8%.
This means that

(a) Give a formula for W , in gigawatts, as a function of time, t , in years since the end of 2014 . W= gigawatts



(b) When is wind capacity predicted to pass 600 gigawatts? Wind capacity will pass 600 gigawatts during the year?
This is t years after the end of 2014, in which t found when W(t) = 600. So




We have that:

So we apply log to both sides of the equality





It will happen 3.1 years after the end of 2014, so during the year of 2018.