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1 year ago

If a shirt selling for $18 is marked upto $20 then the % increase is

Mathematics

2 answers:

luda_lava [24]1 year ago

8 0

Answer:

11%

Step-by-step explanation:

it is a simple question, whenever you need to find % increase or % decrease.

always divide the increase as in this case $2 by the original amount which is $18 and multiply it by 100 as you need to take the %.

so,

2/18*100 gives you 11.11% * is multiply

const2013 [10]1 year ago

6 0

Step-by-step explanation:

$20 - $18 = $2

to get % of increase we need to know what % of $18 the $2 are.

$2 ÷ $18 = 0.11111111........

Multiply this number by 100 and you will get the percentage.

0.111111111111........ x 100 = 11.1111111111....%

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PtichkaEL [24]

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2 years ago

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A set of elementary school student heights are normally distributed with a mean of 105105105 centimeters and a standard deviatio

steposvetlana [31]

Answer:

The proportion of student heights that are between 94.5 and 115.5 is 86.64%

Step-by-step explanation:

We have a mean $\mu = 105$ and a standard deviation $\sigma = 7$ . For a value x we compute the z-score as $(x-\mu)/\sigma$ , so, for x = 94.5 the z-score is (94.5-105)/7 = -1.5, and for x = 115.5 the z-score is (115.5-105)/7 = 1.5. We are looking for P(-1.5 < z < 1.5) = P(z < 1.5) - P(z < -1.5) = 0.9332 - 0.0668 = 0.8664. Therefore, the proportion of student heights that are between 94.5 and 115.5 is 86.64%

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2 years ago

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When Ashley left her house in the morning, her cell phone battery was partially charged. Let BB represent the charge remaining i

Ray Of Light [21]

Answer =

B= 50-10t

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Step-by-step explanation:

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1 year ago

In a data set with a range of 55.4 to 105.4 and 400 observations, there are 176 observations with values less than 86. Find the

IrinaVladis [17]

<u>ANSWER: </u>

In a data set with a range of 55.4 to 105.4 and 400 observations.86 lies in the 49th percentile.

<u>SOLUTION: </u>

Given, in a data set with a range of 55.4 to 105.4 and 400 observations.

There are 176 observations below the value of 86, and we need to find the percentile for 86.

We know that, percentile formula = $\frac{\text {number of observations below the required number}}{\text {total number of observations}} \times 100$