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2 years ago

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A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs

?10. 1m squared floor tiles costs ?3. Work out the total costs of tiles and paints

1 answer:

Darina [25.2K]2 years ago

6 0

Answer:

Total cost for tiles and paints is $924.

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

$\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)$

$\text{Area of walls and ceiling}=1200+90+120$

$\text{Area of walls and ceiling}=1410$

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,

$\text{ The total painting cost}=10*(\frac{1410}{25})$

$\text{ The total painting cost}=10*56.4=564$

Therefore, the total painting cost is $564.

Tiles will be required for floor. Let us find the area of floor.

$\text{Area of floor} = 40*3\text{ square meters}$

$\text{Area of floor} =120\text{ square meters}$

Given: 1m squared floor tiles costs $3. So,

$\text{Total cost for tiles} = 3*120 = 360$

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

$\text{Combined total cost}= 564+360 = 924$

Therefore, the combined total cost of tiles and paint is $924.

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36/4 = 9 per hat
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vova2212 [387]

Answer:

Step-by-step explanation:

A)

y=−2x+4

y-int:

y=−2*0+4

y=4

x-int:

0=−2x+4

2x=4

x=2

(2,4)

B)

2x+3y=6

y-int:

2*0+3y=6

3y=6

y=2

x-int:

2x+3*0=6

2x=6

x=3

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C)

1.2x+2.4y=4.8

y-int:

1.2*0+2.4y=4.8

2.4y=4.8

24y=48

y=2

x-int:

1.2x+2.4*0=4.8

1.2x=4.8

12x=48

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2 years ago

James and his family spend a morning picking peaches. They fill several bags. This line plot shows the weight of each bag.

Mariulka [41]

Answer:

1 1/2

Step-by-step explanation:

The first step is to figure out the lightest and the heaviest bad. The lightest bag is 4 1/4 and the heaviest is 5 3/4. Now to subtract, you can't subtract this as a mixed fraction so turn each fraction into an improper fraction by multiplying the whole number by the denominator then adding the numerator to the product of the whole number multiplied by the denominator (if you didn't know numerator is the top and the denominator is the bottom. To find out 4 1/4 as an improper fraction follow these steps (4*4+1=17) so 4 1/4=17/4. The process is the same for 5 3/4 (5*4+3=23) so 5 3/4= 23/4. Now to subtract, you subtract the numerator but not the denominator. You subtract because the question asks how many more and that means to subtract 23/4-17/4= 6/4. Last step is to turn this back into a mixed fraction do that by dividing the numerator by the denominator, 6 divided by 4 equals 1.5 and turn the decimal into a fraction 1 is a whole number so you don't change that but the 5 behind the decimal needs to be changed so now 1.5= 1 5/10 and last step is simplify 1 1/2. Hope this helped :).

6 0

2 years ago

Read 2 more answers

The sum of two numbers is 0. Twice the smaller number subtracted from 3 times the larger number is 10. Let x represent th larger

slava [35]

The sum of two numbers is zero.
x + y = 0
y = -x

<span>Twice the smaller number subtracted from 3 times the larger number is 10.
Let x represent the larger number and y represent the smaller number.

Twice the smaller number: 2y

3 times the larger number: 3x

</span>Twice the smaller number subtracted from 3 times the larger number is 10.
3x - 2y = 10

-2y = -3x + 10

y = 3/2 x - 5

The equations are:

y = -x
y = 3/2 x - 5

The answer is the first choice.

5 0

2 years ago

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Line segment JL is an altitude in triangle JKM. Which statement explains whether JKM is a right triangle? Round measures to the

natulia [17]

Answer:

C. JKM is not a right triangle because KM ≠ 15.3.

Step-by-step explanation:

We can see from our diagram that triangle JKM is divided into right triangles JLM and JLK.

In order to triangle JKM be a right triangle $KM^{2}=JK^{2}+JM^{2}$ .

We will find length of side KM using our right triangles JLM and JLK as $KM=KL+LM$ .

Using Pythagorean theorem in triangle JLM we will get,

$LM=\sqrt{JM^{2}-JL^{2}}$

$LM=\sqrt{8^{2}-5^{2}}$

$LM=\sqrt{64-25}$

$LM=\sqrt{39}=6.244997998\approx 6.24$

Now let us find length of side KL.

$KL=\sqrt{JK^{2}-JL^{2}}$

$KL=\sqrt{13^{2}-5^{2}}$

$KL=\sqrt{169-25}$

$KL=\sqrt{144}=12$

Now let us find length of KM by adding lengths of KL and LM.

$KM=12+6.24=18.24$

Now let us find whether JKM is right triangle or not using Pythagorean theorem.

$KM^{2}=JK^{2}+JM^{2}$

$18.24^{2}=13^{2}+8^{2}$

$18.24^{2}=169+64$

$18.24^{2}=233$

Upon taking square root of both sides of equation we will get,

$18.24\neq 15.264337522473748$

$18.2\neq 15.3$

We have seen that KM equals 18.2 and in order to JKM be a right triangle KM must be equal to 15.3, therefore, JKM is not a right triangle and option C is the correct choice.

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1 year ago

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