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madreJ [45]
2 years ago
10

A community hall is in the shape of a cuboid the hall is 40m long 15m high and 3m wide. 10 litre paint covers 25m squared costs

?10. 1m squared floor tiles costs ?3. Work out the total costs of tiles and paints
Mathematics
1 answer:
Darina [25.2K]2 years ago
6 0

Answer:

Total cost for tiles and paints is $924.  

Step-by-step explanation:

We have been given that a community hall is in the shape of a cuboid. The hall is 40m long 15m high and 3m wide.

The paint will be required for 4 walls and ceiling.

Let us find area of walls and ceiling.

\text{Area of walls and ceiling}=(2*40*15)+(2*3*15)+(40*3)

\text{Area of walls and ceiling}=1200+90+120

\text{Area of walls and ceiling}=1410

Therefore, the area of walls and ceiling is 1410 square meters.

Given: Cost for 10 litre of paint is $10 and 10 litre paint covers 25 square meter. Therefore,  

\text{ The total painting cost}=10*(\frac{1410}{25})

\text{ The total painting cost}=10*56.4=564

Therefore, the total painting cost is $564.  

Tiles will be required for floor. Let us find the area of floor.

\text{Area of floor} = 40*3\text{ square meters}

\text{Area of floor} =120\text{ square meters}

Given: 1m squared floor tiles costs $3. So,  

\text{Total cost for tiles} = 3*120 = 360

Therefore, the total tiles cost is $360.

Now let us find combined total cost of tiles and paint.

\text{Combined total cost}= 564+360 = 924

Therefore, the combined total cost of tiles and paint is $924.

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Josh works for a construction company that uses 150 pounds of gravel for each driveway they pour. He can buy a dump truck load w
Pavlova-9 [17]

Answer:

Josh should by the dump truck with 30,000 pounds of gravel in it

Step-by-step explanation:

the easiest way to find this out is divide 30,000 and 2,500 by 150 and if the answer is a whole number, then you know that is the correct answer.

30,000/150 = 200

2,500/150 = 16.6666666666666

May I have brainliest please? :)

5 0
1 year ago
A construction company is considering submitting bids for contracts of three different projects. The company estimates that it h
julsineya [31]

Answer:

a.P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

b. E(x) = 0.3

c. S(x)=0.5196

d. E=5,000

Step-by-step explanation:

The probability that the company won x bids follows a binomial distribution because we have n identical and independent experiments with a probability p of success and (1-p) of fail.

So, the PMF of X is equal to:

P(x)=\frac{n!}{x!(n-x)!}*p^{x}*(1-p)^{n-x}\\

Where p is 0.1 and it is the chance of winning. Additionally, n is 3 and it is the number of bids. So the PMF of X is:

P(x)=\frac{3!}{x!(3-x)!}*0.1^{x}*(1-0.1)^{n-x}\\

For binomial distribution:

E(x)=np\\S(x)=\sqrt{np(1-p)}

Therefore, the company can expect to win 0.3 bids and it is calculated as:

E(x) = np = 3*0.1 = 0.3

Additionally, the standard deviation of the number of bids won is:

S(x)=\sqrt{np(1-p)}=\sqrt{3(0.1)(1-0.1)}=0.5196

Finally, the probability to won 1, 2 or 3 bids is equal to:

P(1)=\frac{3!}{1!(3-1)!}*0.1^{1}*(1-0.1)^{3-1}=0.243\\P(2)=\frac{3!}{2!(3-2)!}*0.1^{2}*(1-0.1)^{3-2}=0.027\\P(3)=\frac{3!}{3!(3-3)!}*0.1^{3}*(1-0.1)^{3-3}=0.001

So, the expected profit for the company is equal to:

E=-10,000+50,000(0.243)+100,000(0.027)+150,000(0.001)\\E=5,000

Because there is a probability of 0.243 to win one bid and it will produce 50,000 of income, there is a probability of 0.027 to win 2 bids and it will produce 100,000 of income and there is a probability of 0.001 to win 3 bids and it will produce 150,000 of income.

5 0
2 years ago
Given pre-image ABCDE. Which of the transformations resulted in image Point A'?
mihalych1998 [28]
<span>A(x, y) → (x - 3, y + 1)</span>
8 0
2 years ago
Triangle J K L is shown. Angle J K L is a right angle. An altitude is drawn from point K to point M on side L J to form a right
kompoz [17]

Answer:

LJ=15\ units

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the length side KJ

In the right triangle JKM

Applying the Pythagoras Theorem

KJ^{2}=JM^{2}+KM^{2}

we have

JM=3\ units

KM=6\ units

substitute

KJ^{2}=3^{2}+6^{2}

KJ^{2}=45}

KJ=\sqrt{45}\ units

simplify

KJ=3\sqrt{5}\ units

step 2

Find the value of cosine of angle MJK in the right triangle JKM

cos(JKM)=JM/KJ

substitute the values

cos(JKM)=\frac{3}{3\sqrt{5}}

simplify

cos(JKM)=\frac{\sqrt{5}}{5} -----> equation A

step 3

Find the value of cosine of angle MJK in the right triangle JKL

cos(JKM)=KJ/LJ

we have

KJ=3\sqrt{5}\ units

cos(JKM)=\frac{\sqrt{5}}{5} ----> remember equation A

substitute the values

\frac{\sqrt{5}}{5}=\frac{3\sqrt{5}}{LJ}

Simplify

LJ=5(3)=15\ units

8 0
2 years ago
Read 2 more answers
The number of nails in the bucket is 50 less than twice a number of screws. Together, there are 400 fasteners in the bucket. How
kati45 [8]

Answer:

There are 250 nails and 150 screws in the bucket.

Step-by-step explanation:

Let Number of nails in bucket be x.

Also Let number of screws in the bucket be y.

Together, there are 400 fasteners in the bucket.

Hence the equation can be framed as;

x+y = 400 \ \ \ \ equation \ 1

Also Given:

The number of nails in the bucket is 50 less than twice a number of screws.

Hence the equation can be framed as;

x= 2y -50

Substituting the value of x in equation 1 we get;

x+y=400\\2y-50+y=400\\3y=400+50\\3y=450\\y= \frac{450}{3}=150

Now we have value of y we will substitute in equation 1 we get;

x+y =400\\x+150 =400\\x =400-150\\x=250

Hence there are 250 nails and 150 screws in the bucket.

3 0
2 years ago
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