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Arturiano [62]
2 years ago
14

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold. Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work. Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences. Write the equation in function notation. Explain what the graph of the function represents. Be sure to use complete sentences. Graph the function. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology. Suppose Sal's total profit on lunch specials for the next month is $1,593. The profit amounts are the same: $2 for each sandwich and $3 for each wrap. In a paragraph of at least three complete sentences, explain how the graphs of the functions for the two months are similar and how they are different. Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.
Mathematics
1 answer:
kifflom [539]2 years ago
8 0
This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.

2x + 3y = 1470

2x + 3(0) = 1470

2x = 1470

x = 735

Your furthest point on the x axis is (735,0).

Do the same for y.

2x + 3y = 1470.

2(0) + 3y = 1470

3y= 1470

y= 490

Your highest point is (0,490).

Now that both are plotted, draw a straight line connecting the two points. There's your graph.

Check
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A limited-edition poster increases in value each year with an initial value of $18. After 1 year and an increase of 15% per year
Roman55 [17]

Answer:

The required equation is y = 18(1.15)^x.

Step-by-step explanation:

Consider the provided information.

The Initial value of poster = $ 18

After 1 year amount of increase = $ 20.70

With the rate of 15% = 0.15

Let future value is y and the number of years be x.

y = 18(1.15)^x

Now verify this by substituting x=1 in above equation.

y = 18(1.15)^1=20.7

Which is true.

Hence, the required equation is y = 18(1.15)^x.

7 0
2 years ago
Read 2 more answers
Five less than a number squared is 76, just write equation plz
Volgvan

Answer:

x^{2} - 5 = 76

Step-by-step explanation:

x^{2} = 81

x = 9

3 0
2 years ago
A textbook has 500 pages on which typographical errors could occur. Suppose that there are exactly 10 such errors randomly locat
DiKsa [7]

Answer:

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that the selection of the random pages will contain at least two errors is 0.2644

Step-by-step explanation:

From the information given:

Let q represent the no of typographical errors.

Suppose that there are exactly 10 such errors randomly located on a textbook of 500 pages. Let \mu be the random variable that follows a Poisson distribution, then mean \mu = \dfrac{10}{500}= 0.02

and the mean that the random selection of 50 pages will contain no error is \lambda = 50 \times 0.02 =1

∴

Pr(q= 0) = \dfrac{e^{-1} (1)^0}{0!}

Pr(q =0) = 0.368

The probability of a  selection of 50 pages will contain no errors  is  0.368

The probability that 50 randomly page contains at least 2 errors is computed as follows:

P(X ≥ 2) = 1 - P( X < 2)

P(X ≥ 2) = 1 - [ P(X = 0) + P (X =1 )]    since it is less than 2

P(X \geq 2) = 1 - [ \dfrac{e^{-1} 1^0}{0!} +\dfrac{e^{-1} 1^1}{1!} ]

P(X \geq 2) = 1 - [0.3678 +0.3678]

P(X \geq 2) = 1 -0.7356

P(X ≥ 2) = 0.2644

The probability that the selection of the random pages will contain at least two errors is 0.2644

6 0
2 years ago
In developing an interval estimate for a population mean, a sample of 50 observations was used. the interval estimate was 19.76
alexandr402 [8]

 

The formula for interval estimate would be: μ = M ± Z(<span>sM</span>)

Where: μ is estimate

M is the mean 

Z is the z value

(<span>sM</span>) is the standard error

 

μ = M ± Z(<span>sM</span>)

n = 200 rather than 50 (√200 = 2√50)

<span>⇒ ME = (1/2) * 1.32 = .66</span>

<span>Using the formula above, plugging this in will give us: μ = 19.76 ± .66</span>

<span> = 19.76  ±  .66 is the confidence interval or interval estimate</span>

4 0
2 years ago
we are asking everyone to focus on reducing their average transaction time by 10%. the average transaction time for this locatio
Anettt [7]

Answer:

We have to get the average transaction time down to 371 seconds or 6 minutes 11 seconds.

Step-by-step explanation:

The average transaction time for this location is 6 minutes and 52 seconds.

1\text{ minute}=60\text{ seconds}

6\text{ minute}=6\times 60\text{ seconds}

6\text{ minute}=360\text{ seconds}

The average transaction time for this location is

360+52=412\text{ seconds}

The average transaction time is reduced by 10%.

412-\frac{10}{100}\times 412=412-41.2=370.8\approx 371\text{ seconds}

The average transaction time of this location reduced to 371 seconds.

\frac{371}{60}=\frac{360+11}{60} =6+\frac{11}{60}

The average transaction time of this location reduced to 6 minutes 11 seconds.

6 0
2 years ago
Read 2 more answers
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