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Arturiano [62]
1 year ago
14

Sal's Sandwich Shop sells wraps and sandwiches as part of its lunch specials. The profit on every sandwich is $2 and the profit

on every wrap is $3. Sal made a profit of $1,470 from lunch specials last month. The equation 2x + 3y = 1,470 represents Sal's profits last month, where x is the number of sandwich lunch specials sold and y is the number of wrap lunch specials sold. Change the equation to slope-intercept form. Identify the slope and y-intercept of the equation. Be sure to show all your work. Describe how you would graph this line using the slope-intercept method. Be sure to write using complete sentences. Write the equation in function notation. Explain what the graph of the function represents. Be sure to use complete sentences. Graph the function. On the graph, make sure to label the intercepts. You may graph your equation by hand on a piece of paper and scan your work or you may use graphing technology. Suppose Sal's total profit on lunch specials for the next month is $1,593. The profit amounts are the same: $2 for each sandwich and $3 for each wrap. In a paragraph of at least three complete sentences, explain how the graphs of the functions for the two months are similar and how they are different. Below is a graph that represents the total profits for a third month. Write the equation of the line that represents this graph. Show your work or explain how you determined the equations.
Mathematics
1 answer:
kifflom [539]1 year ago
8 0
This is a very long question. I'm not going to write all of it out but I will give you a starting point. Find your x by making y in the formula equal to 0.

2x + 3y = 1470

2x + 3(0) = 1470

2x = 1470

x = 735

Your furthest point on the x axis is (735,0).

Do the same for y.

2x + 3y = 1470.

2(0) + 3y = 1470

3y= 1470

y= 490

Your highest point is (0,490).

Now that both are plotted, draw a straight line connecting the two points. There's your graph.

Check
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The length of the new tank is 5 times bigger than the old one, so 154×5=770. As a result, the capacity of the new tank is 770L. Hope it help!
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What is the axis of symmetry of h(x) = –2x2 + 12x – 3?
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Little Mexican restaurant sells only two kinds of beef burritos: Mucho beef and Mucho Mucho beef. Last week in the restaurant so
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Step-by-step explanation:

16+22=38

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2 years ago
A coin has a radius of 10 mm. How long will it take the coin to roll through the given angle measure at the given angular veloci
Gemiola [76]

Answer:

t = 1.57 sec

distance, d = 98.65 mm

Step-by-step explanation:

Given an angle of 540°

At 6 revolutions per second, which is the angular velocity.

Radius, r = 10 mm

We are asked to find the time and the distance.

To find the time, let's use the formula:

\theta = a*t

Where \theta = angle in radians.

Converting 540° to radians, we have:

\theta = 540 * \frac{\pi}{180} = 9.42 rad

Therefore, from the formula, let's find t.

\theta = a*t

9.42 = 6 * t

t = \frac{9.42}{6} = 1.57

time = 1.57

To find the distance, we have:

\frac{1.57 * 360}{360} = \frac{d}{2 \pi r}

\frac{1.57 * 360}{360} = \frac{d}{2\pi 10}

1.57 = \frac{d}{20\pi}

d = 20 \pi *1.57

d = 98.65 mm

Therefore, the time is 1.57 seconds and the distance is 98.65 mm

8 0
2 years ago
Two cross sections of a right hexagonal pyramid are obtained by cutting the pyramid with planes parallel to the hexagonal base.
Tanya [424]

Answer:

The larger cross section is 24 meters away from the apex.

Step-by-step explanation:

The cross section of a right hexagonal pyramid is a hexagon; therefore, let us first get some things clear about a hexagon.

The length of the side of the hexagon is equal to the radius of the circle that inscribes it.

The area is

A=\frac{3\sqrt{3} }{2} r^2

Where r is the radius of the inscribing circle (or the length of side of the hexagon).

Now we are given the areas of the two cross sections of the right hexagonal pyramid:A_1=216\:ft^2\: \:\:\:A_2=486\:ft^2

From these areas we find the radius of the hexagons:

r_1=\sqrt{\frac{2A_1}{3\sqrt{3} } } =\sqrt{\frac{2*216}{3\sqrt{3} } }=\boxed{9.12ft}

r_2=\sqrt{\frac{2A_2}{3\sqrt{3} } } =\sqrt{\frac{2*486}{3\sqrt{3} } }=\boxed{13.68ft}

Now when we look at the right hexagonal pyramid from the sides ( as shown in the figure attached ), we see that r_1 r_2 form similar triangles with length H

Therefore we have:

\frac{H-8}{r_1} =\frac{H}{r_2}

We put in the numerical values of r_1, r_2 and solve for H:

\boxed{H=\frac{8r_2}{r_2-r_1} =\frac{8*13.677}{13.68-9.12} =24\:feet.}

8 0
2 years ago
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