Answer:
a) 0.1829
b) 0.6823
c) 0.0413
Step-by-step explanation:
We are given the following information:
We treat adult having little confidence in the newspaper as a success.
P(Adult have little confidence) = 62% = 0.62
Then the number of adults follows a binomial distribution, where
where n is the total number of observations, x is the number of success, p is the probability of success.
Now, we are given n = 10
a) exactly 5
0.1829 is the probability that exactly 5 out of 10 U.S.adults have very little confidence in newspapers.
b) atleast six
0.6823 is the probability that atleast 6 out of 10 U.S. adults have very little confidence in newspapers.
c) less than four
0.0413 is the probability that less than 4 out of 10 U.S. adults have very little confidence in newspapers.
Jenny traveled 70 km/h over 2 hours and 63 km/h over 5 hours. Her travel time was a total of 7 hours.
We need to find out how far she traveled during this 7-hour period.
70 km/h * 2 h = 140 km
63 km/h * 5 h = 315 km
Then, we can add 140 km and 315 km to get a total distance traveled of <em>455 km/h.</em>
We were asked to find the average <em>speed.</em> We can find it now, since we have total distance traveled (455 km) and total time taken (7 hours).
Then,
455km / 7h = 65 km/h.
Answer:
7.5 years
Step-by-step explanation:
P = $5000,
R = 4.25%,
A = $6593.75,
N =?
SI = A - P = 6593.75 - 5000 =$1593. 75
Answer:
Option d. PQ = YZ
Step-by-step explanation:
<u><em>The question in English is</em></u>
Choose the most appropriate answer. The PQR triangle and the XYZ triangle are two congruent triangles. The angle P = the angle Y and PR = YX. Side pairs of the same length are ... a. PQ = XZ b. QR = YZ c. QR = XY d. PQ = YZ
we know that
If two triangles are congruent, then its corresponding sides and its corresponding angles are congruent
Corresponding sides are named using pairs of letters in the same position on either side of the congruence statement
so
we have that
so
Triangle PQR is congruent with Triangle YZX
That means
<em><u>Corresponding angles</u></em>
<u><em>Corresponding sides</em></u>
