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malfutka [58]
2 years ago
14

Janette went to Tire Mart and paid $122.57 per tire for 4 tires and a flat rate fee for installation for a total of $555.28 befo

re taxes. Monique went to Fast Wheels and paid $136.71 per tire for 4 tires and a flat rate fee for installation for a total of $585.34 before taxes. The difference in the amount that they paid in installation charges is
Mathematics
1 answer:
qaws [65]2 years ago
6 0
122.57x4=490.28 is Janette 555.28-490.28=$65 for installation.

Monique 136.71x4=546.84

585.34-546.84=$39 for installation

65-39=$26 is the answer
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Of 100 diners in a restaurant, 45 ordered the fish of the day and 14 are wearing a dress. Of the diners who ordered fish, 8 are
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Karlie makes $8.00 per hour. Karlie worked 16 hours in one week. Karlie wants to purchase a bike that costs $70.00. How much mon
shepuryov [24]

Answer:

58

Step-by-step explanation:


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Consider a picnic. if you want to buy enough hot dogs and buns without having any left over, you need to balance the number of p
Leni [432]
No guarantee that there will enough hotdogs for the buns, we must find the common multiple between the usual number of hot dogs and buns in each package.

Since we're looking for the smallest common multiple between 8 and 10, we can use the method shown below to compute for the least common multiple. 

8 = 2³ 
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LCM = 2³ x 5 = 40

To purchase 40 hot dogs and buns, you need to buy 5 packages of buns and 4 packages of hot dogs.

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Hotdog: 4 packages
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5 0
2 years ago
A computer manufacturer ships laptop computers with the batteries fully charged so that customers can begin to use their purchas
Nataly_w [17]

Answer:

The p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidenc to reject the null hypothesis, and we can said that at 5% of significance the proportion of new laptop's with fully charge for the new model is significantly higher compared to the old model.  

Step-by-step explanation:

1) Data given and notation n  

n=100 represent the random sample taken

X=96 represent the laptop's arrived with fully charged batteries.

\hat p=\frac{96}{100}=0.96 estimated proportion of laptop's arrived with fully charged batteries.

p_o=0.85 is the value that we want to test

\alpha=0.05 represent the significance level  

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the new model’s rate is at least as high as the previous model.:  

Null hypothesis:p \leq 0.85  

Alternative hypothesis:p > 0.85  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.96 -0.85}{\sqrt{\frac{0.85(1-0.85)}{100}}}=3.08  

4) Statistical decision  

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level is not provided, but we can assume \alpha=0.05. The next step would be calculate the p value for this test.  

Since is a one side test the p value would be:  

p_v =P(z>3.08)=0.0010  

So based on the p value obtained and using the significance level assumed \alpha=0.05 we have p_v so we can conclude that we have enough evidenc to reject the null hypothesis, and we can said that at 5% of significance the proportion of new laptop's with fully charge for the new model is significantly higher compared to the old model.  

4 0
2 years ago
A 2.2 GB game is being downloaded onto your laptop. When you have downloaded half a gigabyte, you notice that your computer has
andreev551 [17]

Answer:

0.01m +\frac{1}{2} \geq 2.2

Step-by-step explanation:

Let m be number of minutes it will take to download the whole game.

We are told that computer is downloading at a rate of 0.01 GB per minute and half GB game is already downloaded. So 0.01*m+0.5 will be equal to 2.2 as game size is 2.2 GB.

Let us find the least number of minutes it will take to download the whole game.

0.01m +\frac{1}{2} \geq 2.2

0.01m +0.5\geq 2.2

0.01m \geq 2.2-0.5

0.01m \geq 1.7

m\geq \frac{1.5}{0.01}

Therefore, 0.01m +\frac{1}{2} \geq 2.2 is our desired inequality.



6 0
2 years ago
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