Bob neff owner of an automotive dealership pays one of his salesmen mike a $1300 draw per week plus 6% on all commission sales.

Mathematics

1 answer:

mario62 [17]1 year ago

3 0

To find the answer you would multiply 1,300 by .06, which gives you a commission of $78.

Hope this helps!

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Leonard made some muffins. He gave 5/8 of them to his grandmother and 10 muffins to his aunt. He had 11 muffins left. How many m

elena55 [62]

<span>Leonard made some muffins. He gave 5/8 of them to his grandmother and 10 muffins to his aunt. He had 11 muffins left. How many muffins did he have at first?

If you take 10 and 11 and add, then you'll have 3/8 of the muffins, so 21/3 is 7 and 7*8 is 56, so you'll have 56 muffins to start. and Leonard gave 35 to his grandmother.</span>

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1 year ago

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8.1g of sugar is needed for every cake made. How much sugar is needed for 6 cakes?

Lerok [7]

Answer:

48.6

Step-by-step explanation:

If you use 8.1g of sugar for 1 cake then 6 cakes will be 48.6g of sugar

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2 years ago

Consider the midterm and final for a statistics class. Suppose 13% of students earned an A on the midterm. Of those students who

padilas [110]

Answer:

There is a 38.97% probability that this student earned an A on the midterm.

Step-by-step explanation:

The first step is that we have to find the percentage of students who got an A on the final exam.

Suppose 13% students earned an A on the midterm. Of those students who earned an A on the midterm, 47% received an A on the final, and 11% of the students who earned lower than an A on the midterm received an A on the final.

This means that

Of the 13% of students who earned an A on the midterm, 47% received an A on the final. Also, of the 87% who did not earn an A on the midterm, 11% received an A on the final.

So, the percentage of students who got an A on the final exam is

$P_{A} = 0.13(0.47) + 0.87(0.11) = 0.1568$

To find the probability that this student earned an A on the final test also earned on the midterm, we divide the percentage of students who got an A on both tests by the percentage of students who got an A on the final test.

The percentage of students who got an A on both tests is:

$P_{AA} = 0.13(0.47) = 0.0611$