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Wewaii [24]
2 years ago
11

An old rectangular tank with length 0.3 m could hold 154 L of water. A new similar tank has a length of 1.5 m. What is the capac

ity of the new tank?
Mathematics
2 answers:
dimaraw [331]2 years ago
6 0
The length of the new tank is 5 times bigger than the old one, so 154×5=770. As a result, the capacity of the new tank is 770L. Hope it help!
zimovet [89]2 years ago
5 0
You can use a proportion for this problem.  First, always make sure that the units are the same in both scenarios.  Then you can set up the proportion: (given m of old tank)/(given L of old tank)=(given m of new tank)/x   Let x represent the L in the new tank.  Then cross multiply to solve the proportion.
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1 year ago
a) The curve with equation y2 = x3 + 3x2 is called the Tschirnhausen cubic. Find an equation of the tangent line to this curve a
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Answer:

Tangent at (1,2) has value \frac{15}{4}. And (-2, 4) is the point of intersection of horizontal tangent.

Step-by-step explanation:

Given curve equation,

y^2=x^3+3x^2\hfill (1)

To find tangent at (x,y)=(1,2) and point of intersection of horizontal tangent, differentiate (1) withrespect to x we get,

2y\frac{dy}{dx}=x^3+3x^2

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At (1, 2), tangent line is,

\frac{dy}{dx}|_{(1,2)}}=\frac{15}{4}

To find point of intersection of horizontal tangent we have to do,

\frac{dy}{dx}=0

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Thus,

At x=0, y=0

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\lim_{y\to 0}\frac{dy}{dx}\to \infty

at (0,0) there exist a vertical tangent. And,

At x=-2, y=4.

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2 years ago
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