In Quadrilateral ABCD , AB ∥ CD, and m∠2=35°.
2 answers:
we know that
<u>Alternate interior angles</u> are two interior angles which lie on different parallel lines and on opposite sides of a transversal. Alternate interior angles are congruent
In this problem
the parallel lines are AB and CD
the transversal line is BD
then
m∠5=m∠2 ------> by alternate interior angles
m∠5=
therefore
<u>the answer is</u>
m∠5=
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Answer:
The triangle is an obtuse scalene triangle
Step-by-step explanation:
we know that
if --------> is a right triangle
if --------> is an obtuse triangle
if --------> is an acute triangle
where
c is the greater side
we have
so
so
-------> is an obtuse triangle
Remember that
The given triangle has three different length side
so
Is a scalene triangle
therefore
The triangle is an obtuse scalene triangle
<h3>Answer:</h3>
- f(x) = -2x^3 +3x^2 +11x -6
- see attached
- an infinite number. Since the magnitude of the leading coefficient is not specified, it may be any negative number. (We have chosen the smallest magnitude integer that makes all coefficients be integers.)
1. When "a" is a root of a polynomial, (x -a) is a factor of it. For the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).
In order to make the leading coefficient be negative, we need to multiply this product by a negative number. Any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.
Then ...
... f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)
... = -(2x² +3x -2)(x -3)
... = -(2x³ -3x² -11x +6)
... f(x) = -2x³ +3x² +11x -6
2. A graph created by the Desmos on-line graphing calculator is shown, and the zeros are highlighted.
3. As indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. You want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.