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vodomira [7]
2 years ago
14

a survey asked 50 students if they play an instrument and if they are in band. 25 students play an instrument 20 are in a band a

nd 30 are not in a band. which table shows these data correctly entered in a two way frequency table?

Mathematics
2 answers:
gayaneshka [121]2 years ago
7 0
I would go with d .... If not it would be c...


Really hope I help but I would choose d
anzhelika [568]2 years ago
4 0

Answer:

Option 4th is correct.

Step-by-step explanation:

We have been the information 25 students play an instrument 20 are in a band 30 are not in a band.

We need to create a two way table:

                                      Band            Not in Band       Total

Play instrument                20                   5                     25

Do not play instrument     0                     25                 25

Total                                  20                    30                50

Option 4th is correct.

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Step-by-step explanation:

Answer:

a) y-8 = (y₀-8)  , b) 2y -5 = (2y₀-5)

Explanation:

To solve these equations the method of direct integration is the easiest.

a) the given equation is

          dy / dt = and -8

         dy / y-8 = dt

We change variables

          y-8 = u

         dy = du

We replace and integrate

           ∫ du / u = ∫ dt

           Ln (y-8) = t

We evaluate at the lower limits t = 0 for y = y₀

          ln (y-8) - ln (y₀-8) = t-0

Let's simplify the equation

           ln (y-8 / y₀-8) = t

           y-8 / y₀-8 =

            y-8 = (y₀-8)

b) the equation is

            dy / dt = 2y -5

            u = 2y -5

            du = 2 dy

            du / 2u = dt

We integrate

             ½ Ln (2y-5) = t

We evaluate at the limits

            ½ [ln (2y-5) - ln (2y₀-5)] = t

            Ln (2y-5 / 2y₀-5) = 2t

            2y -5 = (2y₀-5)

c) the equation is very similar to the previous one

             u = 2y -10

             du = 2 dy

             ∫ du / 2u = dt

             ln (2y-10) = 2t

We evaluate

             ln (2y-10) –ln (2y₀-10) = 2t

               2y-10 = (2y₀-10)

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