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Artist 52 [7]
2 years ago
7

The area of a couple's rectangular living room is 40 sq meters. The length of the room is 3 meters more than the width. What is

the width in meters?
Mathematics
1 answer:
kipiarov [429]2 years ago
5 0

the rectangular living room is calculated as length * width

The area is given to be equal to 40 sq. meters (area = 40 sq. meters)

Let the width = x meters

Length = X+3 meters

Area = Length * Width

40 = X * (X+3)

40 = X^2 + 3X

x^2 + 3x -40 =0

We solve this quadratic equation

x^2 + 8x - 5x -40 =0

x*(x+8) -5 *(x+8) =0

(x+8) (x-5) =0

So x = 5 or x= -8

Width  cannot be negative, so we reject x =-8

So x = 5 is the answer

Width of the room = 5 meters

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Step-by-step explanation:

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We simplify the parenthesis to get:

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Therefore the decrease by 15% every time x increases by 1 is

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You have :

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DE arc = ( pi ) ( AD ) ( 2.36 radians / 2 pi radians ) = ( 2/3 ) ( AB ) ( 2.36 radians / 2 )

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BC arc / DE arc = ( AB ) ( 0.59 rad ) / ( 2/3 ) ( AB ) ( 1.18 rad )

BC arc / DE arc = ( 3/2 ) ( .59 rad / 1.18 rad ) = 3/4 <-------

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we know that

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In this problem

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a_sh-v [17]

Let's solve the sine equation.

1. Express sine function in the left side of equation:

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