Answer:
p = 0.293
Conclusion:
"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."
Step-by-step explanation:
------------R/trout--O/trout---bass--catfish---total
GVL - - - 105 - - - 27 - - - - - 35--- 24 - - - 191
EL - - - - 135------- 48-------- 67 - - 43 - - - 293
Total - - 240 - - - 75 - - - - - 102--- 67 - - - 484
Note : GVL = GREEN VALLEY LAKE ; EL = ECHO LAKE.
H0: The distribution of fish caught in green valley is the same as that caught in Echo lake.
H1: The distribution of fish caught in Green Valley lake is different from that caught in Echo valley lake.
Using the chi-squared test statistic calculator ;
χ2 = 3.7269
p-value = 0.2925.
p-value = 0.293
Conclusion:
"There is insufficient evidence to state that the distribution of fish in Green Valley Lake is not the same as the distribution of fish in Echo Lake."
He can cut 5 squares, by making 1 4 × 4, 2 3 × 3 and 2 2 × 2 squares.
Each person gets
of whole pizza
<em><u>Solution:</u></em>
Given that Mia has
of a pizza
She divides it equally among 4 people
<em><u>To find: Fraction of a whole pizza each person gets</u></em>
From statement,
of pizza is divided equally among 4 people
Therefore, to find the fraction of whole pizza each person gets, we can divide the
by 4 people

Thus each person gets
of whole pizza
Since the range of the scores given was between 300 and 700 (which is 2 standard deviations below and above the mean), the probability that a randomly selected student's math score - as based on the empirical rule of statistics - is 95%. In decimal form, it is .95.