General exponential equation
y = A(1+r)^x
where
A = initial value
r = rate increase (+) or decrease (-)
x = time period of the change
y = projected value
y = 300(1.05)^x
in this problem, x = years after 2017
we want to find an x that makes the value more than or equal to 650
650 <= 300(1.05)^x
(9,40,41) is a Pythagorean Triple, farther down the list than teachers usually venture.
Answer: D. 41 cm
There's a subset of Pythagorean Triples where the long leg is one less than the hypotenuse,
a^2+b^2 = (b+1)^2
a^2 + b^2 = b^2 + 2b +1
a^2=2b+1
So we get one for every odd number, since the square of an odd number is odd and the square of an even number is even.
b = (a^2 - 1)/2
a=3, b=(3^2-1)/2=4, c=b+1=5
a=5, b=(5^2-1)/2 =12, c = 13
a=7, b=24, c=25
a=9, b=40, c=41
a=11, b=60, c=61
a=13, b=84, c=85
It's good to be able to recognize Pythagorean Triples when we see them.
Otherwise we'd have to work the calculator:
√(9² + 40²) = √1681 = 41
I would set all 3 given measures equal to 180.
13x-9+4x+11+2x+7 = 180
19x +9 = 180
19x = 171
x= 9
angle l = 4 (9) + 11= 47
answer = 47
Answer:
Possible value of k is √2
Step-by-step explanation:
The information given are;
The expression, 2·(√k - 1) + √8 to which may be added -6·√2 to obtain a rational number, we therefore have;
2·(√k - 1) + √8 - 6·√2 = R
Therefore, simplifying gives;
2·√k - 2 + 2·√2 - 6·√2 = 2·√k - 2 - 4·√2 = R
2·√k - 2 - 4·√2 + 2= R + 2 = R
2·√k - 2+ 2 - 4·√2 = R
2·√k - 2+ 2 - 4·√2 = R
2·√k + 0 - 4·√2 = 2·√k - 4·√2 = 2·(√k - 2·√2) = R
(√k - 2·√2) = R/2 = R
Therefore, √2 is a factor of √k such that √k - 2·√2 = R
Which gives k = x·√2, where x = a rational number
When x = 1, k = √2.
Therefore, a possible value of k is √2
We have
tan 12.5 = 60 / adj rearrange as
adj = 60 / tan 12.5 = about 270.64 m
