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1 year ago

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David read 69 books in a 12-month period. Sarah read 54 books in the same period of time. How many more books per month did Davi

d read than Sarah?

2 answers:

Stels [109]1 year ago

8 0

David = 69
Sarah = 54
69 - 54 = 15
David read 15 more books than Sarah.

koban [17]1 year ago

3 0

David read 15 more books

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The ratio of adams height to sam's height is 4:3 how many times sam's height is adams height

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The <span>ratio of adam's height to sam's height is 4:3. Therefore, Sam's height is 3/4 of adam's height. This is done by applying rules on ratios. We do as follows:

4 / 3 = adam's height / sam's height
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2 years ago

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You are working on an assignment for your statistics class. You need to estimate the proportion of students at your college who

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Answer:

B, Work with the math instructors to create a list of students currently taking a math class. Randomly select

Step-by-step explanation:

Let's think of each scenario at a time.

(A) We select 100 students enrolled in college randomly that should be fine because we are taking only students that can take classes. this rules out faculty members and any other persons but also there may be students that will never take any math course as part of their study plan, this is ruled out on that basis.

(B)if we take 100 students from the list of math instructor, that will ensure that we have taken students that are taking math class now, and math is part of their study plan, seems fine.

(C) visiting cafeteria randomly on multiple days will give us random persons that may not even be enrolled in university. this can be ruled out on that basis.

(D)Ten class at random and surveying each student in every class will make sampling size large or small depending on students enrolled in each of the class this will not give us reliable results.

We can conclude that (B) is the beast method for obtaining reliable results.

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2 years ago

The probability of it snowing in Eastern Canada tomorrow is 0.40.40, point, 4. The probability of it snowing in Western Canada t

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Answer:

<em>They are equally likely to occur</em>

Step-by-step explanation:

<u>Probabilities</u>

The probabilities can be expressed as fractions, decimals or percentages. A probability of 0 indicates an impossible event. A probability of 1 means a sure event. An event is said to be more likely to happen than others if its probability is greater.

We know the probability of it snowing in Eastern Canada tomorrow is 0.40, and we are also aware that the probability of it snowing in Western Canada tomorrow is 2/5. Dividing 2 by 5 we get 0.4. Since both events have the same probability, they are equally likely to occur

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2 years ago

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A stadium has 10500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sec

Hunter-Best [27]

Answer:

1). 875 seats

2). 25 rows in each section

3). $8400

4). Saving of $360

5). 2105 tickets remained unsold

6). x = 16

Step-by-step explanation:

This question is incomplete; here is the complete question.

A stadium has 10,500 seats and 8 VIP boxes. The stadium is divided into 12 equal sections: 2 premium sections and 10 standard sections. A seat at the premium section costs $48 per game. A seat at the standard section costs $27 per game.

1. How many seats are there in each section?

2. If there are 35 seats in each row, how many rows are in each section?

3. If all the seats in the premium section are sold out for a game, how much will the stadium get from those ticket sales?

4. There are 50 games in each season. A season pass costs $2,040. A season pass holder can go to all the games and have a seat in the premium section. How much can a fan save by buying the season pass?

5. For the night game on Tuesday, 8,395 tickets were sold. How many tickets were left?

6. Write an equation using “x” and then solve the equation. Each VIP boxes can seat X people. If all the seats and VIP boxes are filled up, there are 10,628 audience in the stadium.

1). Number of seats in the stadium = 10500

Number of sections = 2 premium + 10 standard = 12

Number of seats in each section = $\frac{10500}{12}=875$

2). If the number of seats in each row = 35

Then number of rows in each section = $\frac{875}{35}=25$

3). Number of seats in 2 premium sections = 2×875 = 1750

Cost of 1750 seats at the rate of $48 per game = 1750 × 48 = $84000

4). Cost of one ticket in premium section = $48 per game

If the games planned in one season = 50

Then cost of the tickets = 48×50 = $2400

Cost of the season ticket = $2040

Saving on the purchase of one season ticket = 2400 - 2040 = $360

5). For a night game number of tickets sold = 8395

Total number of seats in the stadium = 10500

Tickets remained unsold = 10500 - 8395 = 2105

6). Number of seats in each VIP box = x

Number of VIP boxes = 8

Number of seats in 8 VIP boxes = 8x

Total number of tickets sold = 10500 + 8x

Total number of audience in the stadium = 10628

Then the equation will be

8x + 10500 = 10628

8x = 10628 - 10500

x = $\frac{128}{8}=16$

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2 years ago