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Harman [31]
1 year ago
8

Which of the following accurately lists all of the discontinuities for the graph below?

Mathematics
2 answers:
GaryK [48]1 year ago
6 0

Answer:

The answer should be B

Step-by-step explanation:

Short and sweet version of the other guy's answer

Murljashka [212]1 year ago
3 0

Answer:

jump discontinuity at x = 0; point discontinuities at x = –2 and x = 8

Step-by-step explanation:

From the graph we can see that there is a whole in the graph at x=-2.

This is referred to as a point discontinuity.

Similarly, there is point discontinuity at x=8.

We can see that both one sided limits at these points are equal but the function is not defined at these points.

At x=0, there is a jump discontinuity. Both one-sided limits exist but are not equal.

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PLEASE HELP ASAP: A particle is moving with velocity v(t) = t2 – 9t + 18 with distance, s measured in meters, left or right of z
dimaraw [331]
1) \frac{v(8)-v(0)}{8 - 0} = \frac{10-18}{8} = -1\frac{m}{s}.
2) v(5) = 5^2-9*5+18 = 25-45+18 = -2\frac{m}{s}.
3) The particle is moving right when the velocity function is positive: 0\ \textless \ t\ \textless \ 3 or 6\ \textless \ t\ \textless \ 8.
4) When 0\ \textless \ t\ \textless \ \frac{9}{2} the particle is slowing down because the acceleration is close to zero \Rightarrow the particle is speeding up when acceleration is increasing away from zero: \frac{9}{2}\ \textless \ t\ \textless \ 8.
5) (\frac{1}{8})* \int\limits^8_0 {t^2-9t+18dt}=\frac{1}{8}*(\frac{t^3}{3}-(\frac{9}{2}*t^2+18t)_{0}^{8}= \\=(\frac{1}{8})*(\frac{8^3}{3}-(\frac{9}{2})*8^2+18*8)=\frac{8^2}{3}-(\frac{9}{2})*8+18=3\frac{1}{3} \frac{m}{s}.
3 0
2 years ago
Which of the following statements are true of a least - squares regression equation? *
zaharov [31]
Where’s is your problem?
7 0
1 year ago
What’s the 38th term of the arithmetic sequence 31,40,49,58?
Trava [24]

Answer:

a_3_8=364

Step-by-step explanation:

we know that

In an <u><em>Arithmetic Sequence</em></u> the difference between one term and the next is a constant, and this constant is called the common difference

we have

31,40,49,58,...

Let

a_1=31\\a_2=40\\a_3=49\\a_4=58

we have that

a_2-a_1=40-31=9

a_3-a_2=49-40=9

a_4-a_3=58-49=9

so

The common difference is equal to 9

We can write an Arithmetic Sequence as a rule:

a_n=a_1+d(n-1)

where

a_n is the nth term                                                              

a_1 is the first term

d is the common difference                        

n is the number of terms

Find the 38th term of the arithmetic sequence

we have                  

a_1=31\\d=9\\n=38              

substitute the values

a_3_8=31+9(38-1)

a_3_8=31+9(37)

a_3_8=364

3 0
2 years ago
A population of beavers decreases exponentially at a rate of 7.5% per year. What is the equivalent monthly rate to the nearest h
Fiesta28 [93]

Answer:

0.63%


Step-by-step explanation:

If 7.5% decrease in 1 year (12 months), then the percentage decrease per month will be 7.5% divided by 12.

\frac{7.5}{12}=0.625 percent per month


Rounded to the nearest hundredth, 0.625% is equal to 0.63%


3 0
2 years ago
Read 2 more answers
Jillian’s school is selling tickets for a play. The tickets cost $10.50 for adults and $3.75 for students. The ticket sales for
sergij07 [2.7K]

Answer:

The number of adults tickets sold   = 168.

Step-by-step explanation:

The cost of 1 adult ticket  = $10.50

The cost of 1 student ticket =  $3.75

The total sales from the ticket = $2071.50

Now, here let us assume

The number of adult tickets sold  = a

The number of student tickets sold  = b

So, the equation is given as :

10.50 a + 3.75 b = 2071.50

Now, its given the number of students  = 82

⇒ <u>b  =  82</u>

Putting the value of b in the above equation,w e get:

10.50 a + 3.75 ( 82) =  2071. 50

or, 10.50 a  = 2071.50 - 307.5 =  1764

or, a = 1764/10.5 =  168

Hence, the number of adults tickets sold  = a = 168.

3 0
2 years ago
Read 2 more answers
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