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2 years ago

The sample variance of hourly wages was 10. what is the sample standard deviation?

1 answer:

8 0

Standard deviation is defined as the quantity which expresses by how much the members of a group is different from the mean value for the group.

The sample standard deviation with a sample variance of hourly wages 10 will be $3.16.

Explanation:

The standard deviation is the square root of the variance.
Therefore,
The square root of 10 dollars can be calculated as:

√10 = $3.16

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The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillat

Greeley [361]

Answer:

1) $L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

2) $T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

3) $T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

Step-by-step explanation:

Part 1

For this case we know the following info: The length, l cm, of a simple pendulum is directly proportional to the square of its period (time taken to complete one oscillation), T seconds.

$L \propto T^2$

Using the condition given:

$2.205 m = K (3)^2$

$K = 0.245 \approx \frac{g}{4\pi^2}$

So then if we want to create an equation we need to do this:

$L = K T^2$

With K a constant. For this case the period of a pendulumn is given by this general expression:

$T = 2\pi \sqrt{\frac{L}{g}}$

Where L is the length in m and g the gravity $g = 9.8 \frac{m}{s^2}$ .

Part 2

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

If we square both sides of the equation we got:

$T^2 = 4 \pi^2 \frac{L}{g}$

And solving for L we got:

$L = \frac{g T^2}{4 \pi^2}$

Replacing we got:

$L =\frac{9.8 \frac{m}{s^2} (5s)^2}{4 \pi^2} = 6.206m$

Part 3

For this case using the function in part a we got:

$T = 2\pi \sqrt{\frac{L}{g}}$

Replacing we got:

$T = 2\pi \sqrt{\frac{0.98m}{9.8\frac{m}{s^2}}}= 1.987 s$

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2 years ago

Ed buys a vase for £24 and adds 25% onto the price before putting it into his shop window.

lianna [129]

After the 25% discount the vase would cost $18.00

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2 years ago

(01.02 LC)Simplify 9 − (−4).

levacccp [35]

Answer:

Step-by-step explanation:

When we subtract a negative, it is like adding

9 - -4

9 +4

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A four-person committee is chosen from a group of eight boys and six girls. If students are chosen at random, what is the probab

Lapatulllka [165]

Answer: 0.07

Step-by-step explanation:

in the group, we can have only 4 persons.

we have 8 boys, and 6 girls.

We want to find the probability that in the comite we have only boys.

Ok, for the first selection, the probability of selecting a boy is equal to the number of boys divided the total number of the group ( 8 + 6 = 14) this is

p1 = 8/14.

For the second selection we do the same, but we already slected a boy, so now the number of boys is 7, and the total number of posibilities is 13.

p2 = 7/13.

for the third selection we do the same, in this case the probability is

p3 = 6/12

for the fourth selection the probability will be:

p4 = 5/11

The joint probability, of all the events happening at the same time, is equal to the product of the singular probabilities:

P = p1*p2*p3*p4 = (8/14)*(7/13)*(6/12)*(5/11) = 0.07

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*20 points* Complete the proof. Prove: △TUW ≅ △SVW

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B) ASA Congruence

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