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slega [8]
2 years ago
14

The manufacturer of a certain type of new cell phone battery claims that the average life span of the batteries is 500 charges;

that is, the battery can be charged at least 500 times before failing. To investigate the claim, a consumer group will select a random sample of cell phones with the new battery and use the phones through 500 charges of the battery.a. If the claim is true, what is P( X ≤ 36.7) ?b. Based on the answer to part (a), if the claim is true, is a sample mean lifetime of 36.7 hours unusually short?c. If the sample mean lifetime of the 100 batteries were 36.7 hours, would you find the manufacturer's claim to be plausible? Explain.d. If the claim is true, what is P( X ≤ 39.8)?e. Based on the answer to part (d), if the claim is true, is a sample mean lifetime of 39.8 hours unusually short?f. If the sample mean lifetime of the 100 batteries were 39.8 hours, would you find the manufacturer's claim to be plausible? Explain.

Mathematics
1 answer:
maxonik [38]2 years ago
8 0

Answer:

a. 0

b. Yes

c. The manufacturers claim is not plausible

d. 0.3446

e. A sample mean life time of 39.8hr is not unusually short.

f. The manufacturers claim us plausible

Step-by-step explanation:

Please see attachment

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The sound intensity of rustling leaves,  y = 20 decibels

<u>Step-by-step explanation:</u>

y = 10logx

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x = ratio of intensity of sound to reference to intensity

x = 100:1 or x = 100

y = 10 log(100) = 10 * 2 = 20 decibels

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Answer:

1/10

Step-by-step explanation:

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2 years ago
The percent of tom's budget he spends on different types of expenses is shown in the circle graph above.tom's total monthly budg
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Answer:

Groceries is 625 a month

Step-by-step explanation:

25 percent of 2500 is 625. To get this answer take the percent and go back 2 decimal places this will turn 25% into 0.25 then multiply 2500 by 0.25 and the answer is 625. This also is the same with the other values. 0.30 0.15 etc.

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A certain cylindrical tank holds 20,000 gallons of water which can be drained from the bottom of the tank in 20 minutes the volu
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Answer:

Impossible. t=30 minutes.

Step-by-step explanation:

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v(t)=20000(1-\frac{t}{20})^2

Where v(t) represents the amount of gallons remaining after t minutes.

We want to find at what time t is the <em>instanteous </em>rate of change from the tank 1000 gallons per minute.

In order to determine the instantaneous rate of change, let's find the derivative of our function. So, take the derivative of both sides with respect to our time t:

\frac{d}{dt}[v(t)]=\frac{d}{dt}(20000(1-\frac{t}{20})^2]

On the right, let's move the coefficient outside:

v'(t)=20000\frac{d}{dt}[(1-\frac{t}{20})^2]

To differentiate, let's use the chain rule, which is:

u(v(x))=u'(v(x))\cdot v'(x)

Our u(x) is x² and v(x) is (1-t/20). So, u'(x) is 2x and v'(x) is -1/20. Therefore:

v'(t)=20000(2(1-\frac{t}{20})\cdot -\frac{1}{20})

Simplify:

v'(t)=-1000(2(1-\frac{t}{20}))

Simplify:

v'(t)=-1000(2-\frac{t}{10})

Distribute:

v'(t)=100t-2000

So, the instantaneous rate of change after time t is given by the above function.

To find when the instantaneous rate of change of the water is 1000 gallons per minute, substitute 100 for v'(t) and solve for t. So:

1000=100t-2000

Solve for t. Add 2000 to both sides:

3000=100t

Divide both sides by 100:

t=30

So, after 30 minutes, the instantaneous rate of change will be 1000 gallons per minute.

However, if we go back to our original function, our domain t is only defined between 0 and 20 minutes.

So, it is impossible for our instantaneous rate of change to ever reach 1000 gallons per minute.

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Answer:yo

Step-by-step explanation:yo

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