Answer: 14
Step-by-step explanation: 9 small squares with one teddy bear in each, 4 medium squares with 4 bears in each medium square, and 1 big square for the entire thing.
Answer:
Thirty-two percent of fish in a large lake are bass. Imagine scooping out a simple random sample of 15 fish from the lake and observing the sample proportion of bass. What is the standard deviation of the sampling distribution? Determine whether the 10% condition is met.
A. The standard deviation is 0.8795. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
B. The standard deviation is 0.8795. The 10% condition is not met because there are less than 150 bass in the lake.
C. The standard deviation is 0.1204. The 10% condition is met because it is very likely there are more than 150 bass in the lake.
D. The standard deviation is 0.1204. The 10% condition is not met because there are less than 150 bass in the lake.
E. We are unable to determine the standard deviation because we do not know the sample mean. The 10% condition is met because it is very likely there are more than 150 bass in the lake
The answer is E.
Answer:
Kindly check explanation
Step-by-step explanation:
The alpha level set at the beginning of of an experiment is used by the researcher to the limit the probability if making a type 1 error. The type 1 error is committed when a true null hypothesis is incorrectly rejected.
The type 2 error on the other hand is committed when fail to reject a false null hypothesis.
Hence, in other to forestall the risk of incorrectly rejecting a true null hypothesis, the alpha level is set.
When critical region is split across both tails of the distribution, The z-score boundaries at an alpha level α = .05
α = .05 (95% confidence level)
When region is split into 2:
α/2 = .05/2
α/2 = 0.025
Loooking up the z table for the Zscore with probability of 0.025
Zscore = ±1.96
We have that the spring is going to have a sin or a cos equation. We have that the maximum distance of the spring is 6 inches and it is achieved at t=0. Let's fix this as the positive edge. Until now, we have that the function is of the form:
6sin(at+B). We have that the period is 4 minutes and hence that the time component in the equation needs to make a period (2pi) in 4 minutes. Thus 4min*a=2p, a=2p/4=pi/2. In general, a=2pi/T where a is this coefficient, T is the period. Finally, for B, since sin(pi/2)=1, we have that B=pi/2 because when t=0, we have that 6sin(B)=6. Substituting, we have f(t)=6sin(pi*t/2+pi/2)=6cos(pi*t/2)
by trigonometric identities.
All you have to do is substitute all the Xs to and get a final y output.
for example:
if we take the number x is -1 all you do is:
y=-4(-1)+2
y=4+2
y=6
thats the first one done
