Answer:
(1). y = x ~ Exp (1/3).
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
Step-by-step explanation:
Kindly check the attachment to aid in understanding the solution to the question.
So, from the question, we given the following parameters or information or data;
(A). The probability in which attempt to establish a video call via some social media app may fail with = 0.1.
(B). " If connection is established and if no connection failure occurs thereafter, then the duration of a typical video call in minutes is an exponential random variable X with E[X] = 3. "
(C). "due to an unfortunate bug in the app all calls are disconnected after 6 minutes. Let random variable Y denote the overall call duration (i.e., Y = 0 in case of failure to connect, Y = 6 when a call gets disconnected due to the bug, and Y = X otherwise.)."
(1). Hence, for FY(y) = y = x ~ Exp (1/3) for the condition that zero is equal to y = x < 6.
(2). Check attachment.
(3). EY = 3(1 - e^-2).
(4). Var[y] = 3(1 - e^-2) (1 -3 (1 - e^-2)) - 36e^-2.
The condition to follow in order to solve this question is that y = 0 if x ≤ 0, y = x if 0 ≤ x ≤ 6 and y = 6 if x ≥ 6.
Answer:
The Median should be 89.5
And the mean should be 69.75
I hope that helped
Answer:
120 pounds
Step-by-step explanation:
We can use systems of equations to solve this problem. Assuming j is Jim's weight and b is Bob's weight, the equations are:
j + b = 180
b - j = 1/2b
Let's get b - j = 1/2b into standard form (b, then j, then the equal sign, then the constant.)
Now we can solve using the process of elimination.
Now we know how much Bob weighs, for fun, let's find Jim's weight by substituting into the equation.
So Bob weighs 120 pounds and Jim weight 60 pounds.
Hope this helped!
Answer: 0.6827
Step-by-step explanation:
Given : The resistance of a strain gauge is normally distributed .
Population mean : 
Standard deviation : 
Let x be the random variable that represents the resistance of a strain gauge is normally distributed .
z-score : 
To meet the specification, the resistance must be within the range 100±0.7 ohms i.e. (99.3,100.7).
For x = 100.7
For x = 99.3
By using the standard normal distribution table, The proportion of gauges is acceptable is given by:-
Hence, the proportion of gauges is acceptable=0.6827
Answer:
AB = √18 , BC=√18 and CA =4
AB²+BC² = CA² and AB=BC
ΔABC isosceles right angled triangle.
Step-by-step explanation:
Given vectors are 7j+ 10k,-i + 6j+6k and - 4i + +9j + 6k
A( 0,7,10), B( -1,6,6) C(-4,9,6)
AB⁻ = OB-OA = -I+6j+6k-(7j+10k) = -I-j-4k
AB = 
BC = OC-OB = -4i+9j+6k-(-I+6j+6k) = -3i+3j
BC=
CA = OA-OC = 7j+10k - (- 4i + +9j + 6k ) = 4i-2j+4k
CA = 
Since AB²+BC² = CA²
And AB=BC
Therefore it follows that ΔABC is a right angled isosceles triangle
